anonymous
  • anonymous
the vertex is at(-5,1), and the focus is at(2,1). write the equation and graph.
Mathematics
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anonymous
  • anonymous
the vertex is at(-5,1), and the focus is at(2,1). write the equation and graph.
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Owlfred
  • Owlfred
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anonymous
  • anonymous
distance between vertex & focus= \[\sqrt{(-5-2)^{2}+(1-1)^{2}}= 7\] equation of the axis of the parabola- \[y=1\] so, equation of directrix would be- x = k (k is arbitrary constant to be determined) now, since the directrix is equidistant from vertex as focus, \[(-5-k)/\sqrt{1^{2}}=7\] so, k=-12 so the directrix is x+12=0 so the equaton of the parabola is \[(x+12)/\sqrt{1^{2}}=\sqrt{(x-2)^{2}+(y-1)^{2}}\]
dumbcow
  • dumbcow
equation: \[x = \frac{1}{28}(y-1)^{2}-5\]

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