## anonymous 5 years ago the vertex is at(-5,1), and the focus is at(2,1). write the equation and graph.

1. Owlfred

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2. anonymous

distance between vertex & focus= $\sqrt{(-5-2)^{2}+(1-1)^{2}}= 7$ equation of the axis of the parabola- $y=1$ so, equation of directrix would be- x = k (k is arbitrary constant to be determined) now, since the directrix is equidistant from vertex as focus, $(-5-k)/\sqrt{1^{2}}=7$ so, k=-12 so the directrix is x+12=0 so the equaton of the parabola is $(x+12)/\sqrt{1^{2}}=\sqrt{(x-2)^{2}+(y-1)^{2}}$

3. dumbcow

equation: $x = \frac{1}{28}(y-1)^{2}-5$

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