How do i solve squareroot 2 sinx+1=0

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

How do i solve squareroot 2 sinx+1=0

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

is the 2sinx+1 all under the radical and then it's = to 0 ?
oh sorry just the 2 is under the radical
ok you can isolate the radical by moving everything to the other side. then raise both sides to the power of 2. But i am not sure what varible you are solving for

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

but if sin is the coeffeciant of x then you should be able to divide to get them brake them down but i am not sure of this
oh ok thank you anyway
\[\sqrt{2}\sin x =-1\]\[\sin x =-1/\sqrt{2}\]\[x =\sin^{-1} -1/\sqrt{2}\]\[x =\pi/4\]
I'm sorry\[x =5\pi/4\]
  • l
sqrt_2 . sin_x + 1 = 0 sin_x = -1/sqrt_2 x = -pi/4 or 5pi/4 *

Not the answer you are looking for?

Search for more explanations.

Ask your own question