anonymous
  • anonymous
How do i solve squareroot 2 sinx+1=0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
is the 2sinx+1 all under the radical and then it's = to 0 ?
anonymous
  • anonymous
oh sorry just the 2 is under the radical
anonymous
  • anonymous
ok you can isolate the radical by moving everything to the other side. then raise both sides to the power of 2. But i am not sure what varible you are solving for

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anonymous
  • anonymous
but if sin is the coeffeciant of x then you should be able to divide to get them brake them down but i am not sure of this
anonymous
  • anonymous
oh ok thank you anyway
anonymous
  • anonymous
\[\sqrt{2}\sin x =-1\]\[\sin x =-1/\sqrt{2}\]\[x =\sin^{-1} -1/\sqrt{2}\]\[x =\pi/4\]
anonymous
  • anonymous
I'm sorry\[x =5\pi/4\]
l
  • l
sqrt_2 . sin_x + 1 = 0 sin_x = -1/sqrt_2 x = -pi/4 or 5pi/4 *

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