## anonymous 5 years ago How do i solve squareroot 2 sinx+1=0

1. anonymous

is the 2sinx+1 all under the radical and then it's = to 0 ?

2. anonymous

oh sorry just the 2 is under the radical

3. anonymous

ok you can isolate the radical by moving everything to the other side. then raise both sides to the power of 2. But i am not sure what varible you are solving for

4. anonymous

but if sin is the coeffeciant of x then you should be able to divide to get them brake them down but i am not sure of this

5. anonymous

oh ok thank you anyway

6. anonymous

$\sqrt{2}\sin x =-1$$\sin x =-1/\sqrt{2}$$x =\sin^{-1} -1/\sqrt{2}$$x =\pi/4$

7. anonymous

I'm sorry$x =5\pi/4$

8. L

sqrt_2 . sin_x + 1 = 0 sin_x = -1/sqrt_2 x = -pi/4 or 5pi/4 *