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anonymous
 5 years ago
5(2j) + (2j3)
105j +2j3
103j3
= 73j
is that correc t
anonymous
 5 years ago
5(2j) + (2j3) 105j +2j3 103j3 = 73j is that correc t

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immanuelv
 5 years ago
Best ResponseYou've already chosen the best response.0yes ... your work is correct...and so is the answer....!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is this ne correct can you guys check please

immanuelv
 5 years ago
Best ResponseYou've already chosen the best response.013 is not divisible by 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its actually a 12 not a 13

immanuelv
 5 years ago
Best ResponseYou've already chosen the best response.0the correct answer is (12/13)  (6x/13) this is the final answer! :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0still dont understand sorry

immanuelv
 5 years ago
Best ResponseYou've already chosen the best response.0none of them are divisible..... therefore your only hope is to multiply them out when you multiply (1/13)(126x) together, you get 12/13  6x/13 now does it at least makes sum kinda sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry its actually 1/3 not 1/13

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how canyou show me the steps

immanuelv
 5 years ago
Best ResponseYou've already chosen the best response.0of course... so your steps were correct but u forgot about the 6. when you multiply (1/3)(126x) together, you get (1/3)(12)  (1/3)(6x) basically you are dividing them by 3 12 /3 =4 6x/3= 2x therefore it is 42x

immanuelv
 5 years ago
Best ResponseYou've already chosen the best response.0if it is (34 y ) then yes!!!! :)

immanuelv
 5 years ago
Best ResponseYou've already chosen the best response.0i thought i saw a "y" but never mind .... it is 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so my equation is correct

immanuelv
 5 years ago
Best ResponseYou've already chosen the best response.0.... what happened to the y on the top?
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