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6^((log_36)^4)=6 ^ ( log

what base log is that?

6^((log_36)^4)=6 ^ ( (log 6^2 )^4 = 2^4 = 16

Thats what I did, but when I put it into my hmwk (online) then it was wrong...?

one sec

6^((log_36)^4) = 6 ^ [ (log_6 6^2) ^4 ] = 6 ^ [ 2^4] = 6^16

Oh, so I cancelled too many 6's?

dunno, did my solution make sense?

2 821 109 907 456

but thats the right answer, correct ?

6^16=2.821109907e^12 , not sure gonna try

not right

no dont approximate

2 821 109 907 456

why no decimal

theres no need for it

what base is the log?

went to the end, and it showed me the answer is 2

yeah, you probably should give us the whole question

I did

it says to simplify that equation i gave

what base is the log?

I'm confused about that to, i think its 6

\[6^{\log _{36^{4}}} = .....
.\log _{6^{x}}=\log6^{2\times4}......x=8..........6^{8}\]
?

no, I dont think the 4 is a power of 36

at the bottom eqution can u try rewrite

\[6^{\log _{36}4}\]

\[36=6^{2}\]\[36^{x}=4\]\[6^{2(x)}=4\]\[2x=4\]\[x=\frac{4}{2}\]\[x=2\]