Am I doing this problem right? 6^((log_36)^4)=16

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Am I doing this problem right? 6^((log_36)^4)=16

Mathematics
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6^((log_36)^4)=6 ^ ( log
what base log is that?
6^((log_36)^4)=6 ^ ( (log 6^2 )^4 = 2^4 = 16

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Other answers:

Thats what I did, but when I put it into my hmwk (online) then it was wrong...?
one sec
6^((log_36)^4) = 6 ^ [ (log_6 6^2) ^4 ] = 6 ^ [ 2^4] = 6^16
Oh, so I cancelled too many 6's?
dunno, did my solution make sense?
2 821 109 907 456
um, it did but I'm confused still. It doesn't match very well with what I'm getting, well it is but it's not pretty.
but thats the right answer, correct ?
6^16=2.821109907e^12 , not sure gonna try
not right
no dont approximate
2 821 109 907 456
why no decimal
theres no need for it
what base is the log?
went to the end, and it showed me the answer is 2
yeah, you probably should give us the whole question
I did
it says to simplify that equation i gave
what base is the log?
I'm confused about that to, i think its 6
\[6^{\log _{36^{4}}} = ..... .\log _{6^{x}}=\log6^{2\times4}......x=8..........6^{8}\] ?
no, I dont think the 4 is a power of 36
at the bottom eqution can u try rewrite
It's ok, I moved on from that question so you dont need to waste your brain power on this question. Thanks for trying :)
\[6^{\log _{36}4}\]
ahh base is 36 and 4 is not an exponent x = log base 36 (4) => 36^x = 4 => 6^2x = 4 thus x = log base 6 (4) /2 6^x = sqrt(4) = 2
I didn't understand that other answer, but it went away before i could finish looking. I understand yours a little better.
\[36=6^{2}\]\[36^{x}=4\]\[6^{2(x)}=4\]\[2x=4\]\[x=\frac{4}{2}\]\[x=2\]

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