## anonymous 5 years ago Am I doing this problem right? 6^((log_36)^4)=16

1. anonymous

6^((log_36)^4)=6 ^ ( log

2. anonymous

what base log is that?

3. anonymous

6^((log_36)^4)=6 ^ ( (log 6^2 )^4 = 2^4 = 16

4. anonymous

Thats what I did, but when I put it into my hmwk (online) then it was wrong...?

5. anonymous

one sec

6. anonymous

6^((log_36)^4) = 6 ^ [ (log_6 6^2) ^4 ] = 6 ^ [ 2^4] = 6^16

7. anonymous

Oh, so I cancelled too many 6's?

8. anonymous

dunno, did my solution make sense?

9. anonymous

2 821 109 907 456

10. anonymous

um, it did but I'm confused still. It doesn't match very well with what I'm getting, well it is but it's not pretty.

11. anonymous

but thats the right answer, correct ?

12. anonymous

6^16=2.821109907e^12 , not sure gonna try

13. anonymous

not right

14. anonymous

no dont approximate

15. anonymous

2 821 109 907 456

16. anonymous

why no decimal

17. anonymous

theres no need for it

18. dumbcow

what base is the log?

19. anonymous

went to the end, and it showed me the answer is 2

20. anonymous

yeah, you probably should give us the whole question

21. anonymous

I did

22. anonymous

it says to simplify that equation i gave

23. dumbcow

what base is the log?

24. anonymous

I'm confused about that to, i think its 6

25. anonymous

$6^{\log _{36^{4}}} = ..... .\log _{6^{x}}=\log6^{2\times4}......x=8..........6^{8}$ ?

26. anonymous

no, I dont think the 4 is a power of 36

27. anonymous

at the bottom eqution can u try rewrite

28. anonymous

It's ok, I moved on from that question so you dont need to waste your brain power on this question. Thanks for trying :)

29. anonymous

$6^{\log _{36}4}$

30. dumbcow

ahh base is 36 and 4 is not an exponent x = log base 36 (4) => 36^x = 4 => 6^2x = 4 thus x = log base 6 (4) /2 6^x = sqrt(4) = 2

31. anonymous

I didn't understand that other answer, but it went away before i could finish looking. I understand yours a little better.

32. anonymous

$36=6^{2}$$36^{x}=4$$6^{2(x)}=4$$2x=4$$x=\frac{4}{2}$$x=2$