anonymous
  • anonymous
Am I doing this problem right? 6^((log_36)^4)=16
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
6^((log_36)^4)=6 ^ ( log
anonymous
  • anonymous
what base log is that?
anonymous
  • anonymous
6^((log_36)^4)=6 ^ ( (log 6^2 )^4 = 2^4 = 16

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Thats what I did, but when I put it into my hmwk (online) then it was wrong...?
anonymous
  • anonymous
one sec
anonymous
  • anonymous
6^((log_36)^4) = 6 ^ [ (log_6 6^2) ^4 ] = 6 ^ [ 2^4] = 6^16
anonymous
  • anonymous
Oh, so I cancelled too many 6's?
anonymous
  • anonymous
dunno, did my solution make sense?
anonymous
  • anonymous
2 821 109 907 456
anonymous
  • anonymous
um, it did but I'm confused still. It doesn't match very well with what I'm getting, well it is but it's not pretty.
anonymous
  • anonymous
but thats the right answer, correct ?
anonymous
  • anonymous
6^16=2.821109907e^12 , not sure gonna try
anonymous
  • anonymous
not right
anonymous
  • anonymous
no dont approximate
anonymous
  • anonymous
2 821 109 907 456
anonymous
  • anonymous
why no decimal
anonymous
  • anonymous
theres no need for it
dumbcow
  • dumbcow
what base is the log?
anonymous
  • anonymous
went to the end, and it showed me the answer is 2
anonymous
  • anonymous
yeah, you probably should give us the whole question
anonymous
  • anonymous
I did
anonymous
  • anonymous
it says to simplify that equation i gave
dumbcow
  • dumbcow
what base is the log?
anonymous
  • anonymous
I'm confused about that to, i think its 6
anonymous
  • anonymous
\[6^{\log _{36^{4}}} = ..... .\log _{6^{x}}=\log6^{2\times4}......x=8..........6^{8}\] ?
anonymous
  • anonymous
no, I dont think the 4 is a power of 36
anonymous
  • anonymous
at the bottom eqution can u try rewrite
anonymous
  • anonymous
It's ok, I moved on from that question so you dont need to waste your brain power on this question. Thanks for trying :)
anonymous
  • anonymous
\[6^{\log _{36}4}\]
dumbcow
  • dumbcow
ahh base is 36 and 4 is not an exponent x = log base 36 (4) => 36^x = 4 => 6^2x = 4 thus x = log base 6 (4) /2 6^x = sqrt(4) = 2
anonymous
  • anonymous
I didn't understand that other answer, but it went away before i could finish looking. I understand yours a little better.
anonymous
  • anonymous
\[36=6^{2}\]\[36^{x}=4\]\[6^{2(x)}=4\]\[2x=4\]\[x=\frac{4}{2}\]\[x=2\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.