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anonymous

  • 5 years ago

Am I doing this problem right? 6^((log_36)^4)=16

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  1. anonymous
    • 5 years ago
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    6^((log_36)^4)=6 ^ ( log

  2. anonymous
    • 5 years ago
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    what base log is that?

  3. anonymous
    • 5 years ago
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    6^((log_36)^4)=6 ^ ( (log 6^2 )^4 = 2^4 = 16

  4. anonymous
    • 5 years ago
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    Thats what I did, but when I put it into my hmwk (online) then it was wrong...?

  5. anonymous
    • 5 years ago
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    one sec

  6. anonymous
    • 5 years ago
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    6^((log_36)^4) = 6 ^ [ (log_6 6^2) ^4 ] = 6 ^ [ 2^4] = 6^16

  7. anonymous
    • 5 years ago
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    Oh, so I cancelled too many 6's?

  8. anonymous
    • 5 years ago
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    dunno, did my solution make sense?

  9. anonymous
    • 5 years ago
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    2 821 109 907 456

  10. anonymous
    • 5 years ago
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    um, it did but I'm confused still. It doesn't match very well with what I'm getting, well it is but it's not pretty.

  11. anonymous
    • 5 years ago
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    but thats the right answer, correct ?

  12. anonymous
    • 5 years ago
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    6^16=2.821109907e^12 , not sure gonna try

  13. anonymous
    • 5 years ago
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    not right

  14. anonymous
    • 5 years ago
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    no dont approximate

  15. anonymous
    • 5 years ago
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    2 821 109 907 456

  16. anonymous
    • 5 years ago
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    why no decimal

  17. anonymous
    • 5 years ago
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    theres no need for it

  18. dumbcow
    • 5 years ago
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    what base is the log?

  19. anonymous
    • 5 years ago
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    went to the end, and it showed me the answer is 2

  20. anonymous
    • 5 years ago
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    yeah, you probably should give us the whole question

  21. anonymous
    • 5 years ago
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    I did

  22. anonymous
    • 5 years ago
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    it says to simplify that equation i gave

  23. dumbcow
    • 5 years ago
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    what base is the log?

  24. anonymous
    • 5 years ago
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    I'm confused about that to, i think its 6

  25. anonymous
    • 5 years ago
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    \[6^{\log _{36^{4}}} = ..... .\log _{6^{x}}=\log6^{2\times4}......x=8..........6^{8}\] ?

  26. anonymous
    • 5 years ago
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    no, I dont think the 4 is a power of 36

  27. anonymous
    • 5 years ago
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    at the bottom eqution can u try rewrite

  28. anonymous
    • 5 years ago
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    It's ok, I moved on from that question so you dont need to waste your brain power on this question. Thanks for trying :)

  29. anonymous
    • 5 years ago
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    \[6^{\log _{36}4}\]

  30. dumbcow
    • 5 years ago
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    ahh base is 36 and 4 is not an exponent x = log base 36 (4) => 36^x = 4 => 6^2x = 4 thus x = log base 6 (4) /2 6^x = sqrt(4) = 2

  31. anonymous
    • 5 years ago
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    I didn't understand that other answer, but it went away before i could finish looking. I understand yours a little better.

  32. anonymous
    • 5 years ago
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    \[36=6^{2}\]\[36^{x}=4\]\[6^{2(x)}=4\]\[2x=4\]\[x=\frac{4}{2}\]\[x=2\]

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