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anonymous

  • 5 years ago

Tim kicks a ball off the ground. After t seconds, its height, h (in feet), is given by the formula h=-16t^2+64t. What is the maximum height reached by the ball? 80 feet 64 feet 48 feet 16 feet

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  1. anonymous
    • 5 years ago
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    try plugging in each of your options into the formula as h

  2. anonymous
    • 5 years ago
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    Try to calculate h'(t)=0 and plug that result into h(t)

  3. anonymous
    • 5 years ago
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    wait, im confused...

  4. anonymous
    • 5 years ago
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    with what?

  5. anonymous
    • 5 years ago
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    what you just said

  6. anonymous
    • 5 years ago
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    okay i explain

  7. anonymous
    • 5 years ago
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    h(x) is a parabola right?

  8. anonymous
    • 5 years ago
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    i guess

  9. anonymous
    • 5 years ago
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    tha maximum height of a ball or a parabola is at the point where the slope of it is 0. The slope dy/dt =0 t

  10. anonymous
    • 5 years ago
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    so iput in h(0) then the rest of the formula?

  11. anonymous
    • 5 years ago
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    no you have to calculate h'(t) =0

  12. anonymous
    • 5 years ago
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    \[-32t+64=0 \] \[-t=-2\] \[t=2\]

  13. anonymous
    • 5 years ago
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    Now you have t and can plug it in to h(t) => h(2).

  14. anonymous
    • 5 years ago
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    so i pput h(2) then the rest or the formula?

  15. anonymous
    • 5 years ago
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    h(2) = -16(2)^2 +64(2)

  16. anonymous
    • 5 years ago
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    i got 32, which isnt an answer choice

  17. anonymous
    • 5 years ago
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    -16(2)^2 is -64 | 64(2) is 128

  18. anonymous
    • 5 years ago
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    128-64 is 64

  19. anonymous
    • 5 years ago
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    thank you (: your awsome!

  20. anonymous
    • 5 years ago
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    No problem!

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spraguer (Moderator)
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