Tim kicks a ball off the ground. After t seconds, its height, h (in feet), is given by the formula h=-16t^2+64t. What is the maximum height reached by the ball? 80 feet 64 feet 48 feet 16 feet

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Tim kicks a ball off the ground. After t seconds, its height, h (in feet), is given by the formula h=-16t^2+64t. What is the maximum height reached by the ball? 80 feet 64 feet 48 feet 16 feet

Mathematics
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try plugging in each of your options into the formula as h
Try to calculate h'(t)=0 and plug that result into h(t)
wait, im confused...

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Other answers:

with what?
what you just said
okay i explain
h(x) is a parabola right?
i guess
tha maximum height of a ball or a parabola is at the point where the slope of it is 0. The slope dy/dt =0 t
so iput in h(0) then the rest of the formula?
no you have to calculate h'(t) =0
\[-32t+64=0 \] \[-t=-2\] \[t=2\]
Now you have t and can plug it in to h(t) => h(2).
so i pput h(2) then the rest or the formula?
h(2) = -16(2)^2 +64(2)
i got 32, which isnt an answer choice
-16(2)^2 is -64 | 64(2) is 128
128-64 is 64
thank you (: your awsome!
No problem!

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