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moongazer

  • 5 years ago

given that kx +6y = 1 and 2x + 3y = 1, what should be the value of k so that there will be no solution? Please answer clearly and explain the solution clearly and easy to understand. Thanks! (guaranteed medal for a good answer)

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  1. aroub
    • 5 years ago
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    is this question about slope ?

  2. anonymous
    • 5 years ago
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    At first glance it would seem that k = 4

  3. anonymous
    • 5 years ago
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    Put this into the equation then try to solve simultaneously 4x + 6y = 1 2x + 3y = 1 multiply equation 2 by 2 4x + 6y = 1 4x + 6y = 2 Subtract equation 1 from equation 2 Gives an answer 0=1 So k = 4

  4. anonymous
    • 5 years ago
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    Does that make sense?

  5. moongazer
    • 5 years ago
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    where did you get 4?

  6. anonymous
    • 5 years ago
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    I wanted to equate the LHS of both equations

  7. anonymous
    • 5 years ago
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    ...and I could see that 3y could easily become 6y by multiplication hence 2x can become 4x

  8. anonymous
    • 5 years ago
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    thats a correct solution gian theres his medal moongazer?

  9. anonymous
    • 5 years ago
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    Thank you Jimmy!

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