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cherrilyn
 5 years ago
LEIBNIZ TEST!
cherrilyn
 5 years ago
LEIBNIZ TEST!

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cherrilyn
 5 years ago
Best ResponseYou've already chosen the best response.0why can't it be applied to..... 1/2  1/3 + 1/2^2  1/3^2 + 1/2^3  1/3^3... what method can be used to show convergence?

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1Is the absolute value sequence decreasing?

cherrilyn
 5 years ago
Best ResponseYou've already chosen the best response.0ummmmmmm. . . maybe? lol

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0That sequence definitely looks like a zerosequence to me, so the Leibniztest can be applied. The series converges!

cherrilyn
 5 years ago
Best ResponseYou've already chosen the best response.0um..it says it cannot be applied. and I have to explain why not.

cherrilyn
 5 years ago
Best ResponseYou've already chosen the best response.0It probably seems convergent because I don't know how to use the division sign on here :/

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1Between 1/2^n and 1/2^(n+1) you have 1/3^n. But now 1/2^n > 1/3^n < 1/2^(n+1) So the absolute value sequence is not decreasing, hence we can't apply the Leibniz's test!
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