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cherrilyn

  • 5 years ago

LEIBNIZ TEST!

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  1. cherrilyn
    • 5 years ago
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    why can't it be applied to..... 1/2 - 1/3 + 1/2^2 - 1/3^2 + 1/2^3 - 1/3^3... what method can be used to show convergence?

  2. watchmath
    • 5 years ago
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    Is the absolute value sequence decreasing?

  3. cherrilyn
    • 5 years ago
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    ummmmmmm. . . maybe? lol

  4. nowhereman
    • 5 years ago
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    That sequence definitely looks like a zero-sequence to me, so the Leibniz-test can be applied. The series converges!

  5. anonymous
    • 5 years ago
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    yep

  6. cherrilyn
    • 5 years ago
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    um..it says it cannot be applied. and I have to explain why not.

  7. cherrilyn
    • 5 years ago
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    It probably seems convergent because I don't know how to use the division sign on here :/

  8. watchmath
    • 5 years ago
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    Between 1/2^n and 1/2^(n+1) you have 1/3^n. But now 1/2^n > 1/3^n < 1/2^(n+1) So the absolute value sequence is not decreasing, hence we can't apply the Leibniz's test!

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