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anonymous

  • 5 years ago

how mandy whole numbers are less than 1000 but contain no 8 but at least one 2

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  1. Owlfred
    • 5 years ago
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    Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

  2. anonymous
    • 5 years ago
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    come on. you can figure that out!

  3. nowhereman
    • 5 years ago
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    How can one number 'contain' another?

  4. watchmath
    • 5 years ago
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    There are 999 whole numbers that are less than 1000 (from 1 up to 999) Since we want the numbers to be greater than 1 we need to remove the 1 from the set and also we remove the 8 because we don't want that number. So after removing two numbers we have 999-2=997 numbers.

  5. anonymous
    • 5 years ago
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    think you might have missed this one watchmath. i read it to say "how many three digit numbers are there where none of the digits are 8 and at least one is 2" for example 811 is out as is 345 but 231 is in

  6. anonymous
    • 5 years ago
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    or it could mean how many whole numbers are divisible by 2 but not 8

  7. nowhereman
    • 5 years ago
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    Or it could mean, all numbers greater than 8 and smaller than 2. Because set-theoretically a natural number is the set of all it's predecessors.

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