anonymous
  • anonymous
For what values of y does y^2-2y=48? Show all work.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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amistre64
  • amistre64
-6 and 8
anonymous
  • anonymous
How did you get that?
anonymous
  • anonymous
he is super fast that is how. plus wolfram

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More answers

anonymous
  • anonymous
\[y^2-2y-48=0\] \[(y+6)(y-8)=0\]
amistre64
  • amistre64
sometimes I feel like working it out; others times not lol
anonymous
  • anonymous
\[y+6=0\] \[y=-6\] \[y-8=0\] \[y=8\]
anonymous
  • anonymous
method two \[y^2-2y=48\] \[(y-1)^2=48+1=49\] \[y-1=7\] or \[y-1=-7\] \[y = 8\] or \[y=-6\]
anonymous
  • anonymous
pfft super fast , anyone thats been doing maths for like 4yrs should be able to solve a quadratic like that in about 30seconds
anonymous
  • anonymous
its even monic which makes it even easier!
amistre64
  • amistre64
28.6875378583032847459504348475... secs lol
amistre64
  • amistre64
30 seconds is for my grandma ;)
anonymous
  • anonymous
i still cannot factor to save my life. prefer to find the zeros
amistre64
  • amistre64
the factors are just the zeros in reverse; if x = -3, 5 are roots then (x+3)(x-5) are the factors
amistre64
  • amistre64
maybe should ammend that to have a constant of variation, but you know lol
anonymous
  • anonymous
of course and so to factor i find the zeros. it is easier for me to do it that way
anonymous
  • anonymous
Satelite, thanks for the tip about wolfram. It calculated the answer to "life, the universe, and everything" super-fast !

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