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It depends on where your \(\Theta\) is

hang on i am scanning the diagram

here is the diagram pls answer quickly!!!!!!!!!!

this fairly easy

so answer it pls!!!!!!!!!!!!!

well , just consider the angle between theta1 and the vector mg

so then!!!!!!!!!!

this will be 90 - theta

then do trig in that triangle

fine!!! further ahead!!!!!!!

yeh.. im answering it , its just a bit slow lol

k sorry!!!!!!

i need to know why is the vertical component of say Na NaCos Theta and not Na sin Theta

yeh , its basically because sin(90-x) = cos(x)

lol, thats wrong cos(90-x) = sin(x)

ill draw a picture on paint , hopefully it will help lol

k hopefully!!!!!!!!!!!!

ill do another one

now in the second triganle you apply trig
sin( 90-x) = Na / Fy

but sin(90-x) = cos(x)

so Fy = Na / cos(x)

wait dont think thats right

to be honest I dont really know what you are asking , what is the actual question ?

that is a right angled trangle , and the angle between the track and the y axis is just 90-theta

then you re draw the triangle and apply basic trig ratios and simply sin(90-x) to cos(x)