anonymous
  • anonymous
I have a doubt which needs to be urgently solved cause i got a test tommorow!!!!!!!!The question is in the replies cause i cannot write a diagram or attach a diagram here!!!!! Its physics i know its a wrong section to ask at but i have no choice!!!!!!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
I want to know how can we find the vertical component of the force vector here for normal reaction using \[N _{a}\cos \Theta\] rather than\[N_{a}\sin \Theta\]
watchmath
  • watchmath
It depends on where your \(\Theta\) is
anonymous
  • anonymous
hang on i am scanning the diagram

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anonymous
  • anonymous
here is the diagram pls answer quickly!!!!!!!!!!
1 Attachment
anonymous
  • anonymous
this fairly easy
anonymous
  • anonymous
so answer it pls!!!!!!!!!!!!!
anonymous
  • anonymous
well , just consider the angle between theta1 and the vector mg
anonymous
  • anonymous
so then!!!!!!!!!!
anonymous
  • anonymous
this will be 90 - theta
anonymous
  • anonymous
then do trig in that triangle
anonymous
  • anonymous
fine!!! further ahead!!!!!!!
anonymous
  • anonymous
yeh.. im answering it , its just a bit slow lol
anonymous
  • anonymous
k sorry!!!!!!
anonymous
  • anonymous
i need to know why is the vertical component of say Na NaCos Theta and not Na sin Theta
anonymous
  • anonymous
yeh , its basically because sin(90-x) = cos(x)
anonymous
  • anonymous
lol, thats wrong cos(90-x) = sin(x)
anonymous
  • anonymous
but is that the triangle we can use to do this cause i don't think so!!!!!!! and now i am confused with the two comments u made
anonymous
  • anonymous
can any1 make a quick video and attach it i know i am asking way too much but pls do if possible!!!!!!!!
anonymous
  • anonymous
ill draw a picture on paint , hopefully it will help lol
anonymous
  • anonymous
k hopefully!!!!!!!!!!!!
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
ill do another one
anonymous
  • anonymous
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anonymous
  • anonymous
second picture is just redrawing the top triangle in the previous picture, and marking in what you know
anonymous
  • anonymous
now in the second triganle you apply trig sin( 90-x) = Na / Fy
anonymous
  • anonymous
but sin(90-x) = cos(x)
anonymous
  • anonymous
so Fy = Na / cos(x)
anonymous
  • anonymous
wait dont think thats right
anonymous
  • anonymous
thanks for ur effort but cud u use a the line tool to make the diagram cause this is really strange i am not able to make sense
anonymous
  • anonymous
to be honest I dont really know what you are asking , what is the actual question ?
anonymous
  • anonymous
and if you look at it , the second triangle , the one that has two sides ( one being the y axis and the other being the plane along the track
anonymous
  • anonymous
that is a right angled trangle , and the angle between the track and the y axis is just 90-theta
anonymous
  • anonymous
then you re draw the triangle and apply basic trig ratios and simply sin(90-x) to cos(x)
anonymous
  • anonymous
i am trying to relate it to the concept of vectors which we can represent on the x axis and the y axis!!!!!
anonymous
  • anonymous
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