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anonymous

  • 5 years ago

Can someone teach me how to find the domain of an expression: sqrt(x(x-2))

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  1. amistre64
    • 5 years ago
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    sqrt(a) is valid for all positive a values

  2. amistre64
    • 5 years ago
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    so whatever makes the innards go less than zero is bad

  3. anonymous
    • 5 years ago
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    Since it is a sqrt, you cannot have your value inside to be a negative. So, this means that your x(x-2) >= 0

  4. anonymous
    • 5 years ago
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    I plotted this function and I got:

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  5. amistre64
    • 5 years ago
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    that looks about right; since you got a quadratic in there its gonna act wierd like that

  6. amistre64
    • 5 years ago
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    at 0 and 2 we have roots <...........0.........2.........> - + + - - + ------------------- + - + Domain: (-inf,0] or [2,inf)

  7. anonymous
    • 5 years ago
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    can you show the work, please?

  8. amistre64
    • 5 years ago
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    that is the work

  9. anonymous
    • 5 years ago
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    the formulas. Analitically

  10. anonymous
    • 5 years ago
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    Im really good at finding the domain graphically

  11. amistre64
    • 5 years ago
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    sqrt[x(x-2)] is already factored out .... i really cant see much else to do with it other than plot it on a number line and show the +- ranges

  12. amistre64
    • 5 years ago
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    x = 0 when x = 0 x-2 = 0 when x = 2

  13. anonymous
    • 5 years ago
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    x>=0 x>=2 both inequalities are true

  14. amistre64
    • 5 years ago
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    <...................0.................2................> x<0; - x>0; + + x<2; - - x>2; + ------------------------------------- -*- = + +*-=- +*+=+

  15. amistre64
    • 5 years ago
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    Domain: (-inf,0] or [2,inf)

  16. anonymous
    • 5 years ago
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    ahhh got it

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