anonymous
  • anonymous
Whats the anti derivative of (1/(x^4)) ?? Need Help
Mathematics
katieb
  • katieb
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amistre64
  • amistre64
x^-4 x^-3 ---- i think -3
anonymous
  • anonymous
+C
anonymous
  • anonymous
yep

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amistre64
  • amistre64
\(\frac{-1}{3x^3}+C\) lol
amistre64
  • amistre64
it looks to work like a derivative rule....
anonymous
  • anonymous
\[\int\limits_{}^{}x^{n}dx=x^{n+1}/(n+1)+C\] here n=-4
amistre64
  • amistre64
1/x^4 = -1/3x^3 ....close..
anonymous
  • anonymous
so you dont brink the x ^4 to the numerater?
anonymous
  • anonymous
it's in the denominator so to bring it to the numerator you switch the sign of the exponent
anonymous
  • anonymous
ya i know that , but how is the one negative?
amistre64
  • amistre64
\[\frac{x^{-4+1}}{-4+1}\]
amistre64
  • amistre64
\[\frac{x^-{3}}{-3}\]
amistre64
  • amistre64
\[-\frac{1}{3x^3}\]
anonymous
  • anonymous
thank you

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