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anonymous

  • 5 years ago

what the derivative of 2arctan(2x) ?

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  1. anonymous
    • 5 years ago
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    \[2( \frac{1}{1+4x^2})*2\]

  2. anonymous
    • 5 years ago
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    4[1/(1+4x^2)]

  3. anonymous
    • 5 years ago
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    can you explain a little better how you got that?

  4. anonymous
    • 5 years ago
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    \[{d \over dx }\tan ^{-1}x=/1+x^2\]

  5. anonymous
    • 5 years ago
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    apply this formula for 2arctan(2x)

  6. anonymous
    • 5 years ago
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    instead of x, here we have 2x, so by chain rule next we multiply with the derivative of 2x, that is 2

  7. anonymous
    • 5 years ago
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    is it helpful?

  8. anonymous
    • 5 years ago
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    yes how did you get 4x^2?

  9. anonymous
    • 5 years ago
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    since instead of x,we have 2x.so (2x)^2=4x^2

  10. anonymous
    • 5 years ago
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    ok?

  11. anonymous
    • 5 years ago
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    ahhh gotcha...

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