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anonymous

  • 5 years ago

solve limx4 (sqrt 8-x)-2/(sqrt 5-x)-1

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  1. anonymous
    • 5 years ago
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    can you please show me step by step thanks

  2. angela210793
    • 5 years ago
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    lim x-->4 F(x)=F(4)=sqr (8-4)-2/sqr(5-4)-1=0/0 indefinite form

  3. angela210793
    • 5 years ago
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    so we can use Hopital's rule

  4. angela210793
    • 5 years ago
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    http://en.wikipedia.org/wiki/L'H%C3%B4pital's_rule

  5. angela210793
    • 5 years ago
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    lim x-->4 [(sqr8-x)-2]'/[(sqr5-x)-1]'

  6. angela210793
    • 5 years ago
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    Do u know derivatives?

  7. anonymous
    • 5 years ago
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    i got the denomiator 0 and the numerator zero as well

  8. anonymous
    • 5 years ago
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    not yet im currently taking calc

  9. angela210793
    • 5 years ago
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    yea u can use Hopital's rule when u get 0/0 or infinite/infinite

  10. anonymous
    • 5 years ago
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    ok thanks

  11. angela210793
    • 5 years ago
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    [(sqr8-x)-2]'=1/2sqr(8-x) and [(sqr5-x)-1]'=1/2sqr(5-x) so we'll have 1/2sqr(8-x) 2sqr(5-x) lim x-->4 -------------=lim x-->4------------=1/2 1/2sqr(5-x) 2sqr(8-x)

  12. angela210793
    • 5 years ago
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    Got it?

  13. anonymous
    • 5 years ago
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    yes!! now i understand completely thank you soooo much..Im gonna refer to this as much as i can remeber

  14. angela210793
    • 5 years ago
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    Happy i helped :)

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