anonymous
  • anonymous
The widths of two similar rectangles are 6 m and 21 m. What is the ratio of the perimeters? Of the areas? Possible Answers: A) 3 : 8 and 9 : 64 B) 2 : 7 and 9 : 64 C) 2 : 7 and 4 : 49 D) 3 : 8 and 4 : 49 Thanks!
Mathematics
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SOLVED
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katieb
  • katieb
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amistre64
  • amistre64
6 to 21 = 2 to 7; so its either B or C by that
anonymous
  • anonymous
Ya, I went with C, but it was just a guess
amistre64
  • amistre64
if we assume a height of 6; then the height of the other is 21 36 area and 441 (1 to 12.25) 4 = 4 to 49; C

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anonymous
  • anonymous
Great, I had thought so. Thank you for checking my work!
amistre64
  • amistre64
spose we assume a height of 4; does it still work? 6(4) = 24 (6)(3.5)(4)(3.5) = 294 294/24 = 12.25 ...so yeah...it agrees
anonymous
  • anonymous
Cool. Thank You!

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