anonymous
  • anonymous
14x^3-35x^2+18x-45 Factor by grouping I got the answer that like looks like the problem is that right
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
what's grouping? so many questions so few answers
amistre64
  • amistre64
looks like you can use 5 and 2 to start with..
amistre64
  • amistre64
(14x^3+18x)+(-35x^2-45)

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amistre64
  • amistre64
2x(7x^2 +9) +-5(7x^2+9)
amistre64
  • amistre64
(2x-5) (7x^2+9) then
anonymous
  • anonymous
I think grouping mean taking the polynomial and grouping them together and solved I am not sure that is what I am here for is to get help with my math.
anonymous
  • anonymous
\[\int\limits xdx\]
amistre64
  • amistre64
well, I got it down to a linear and a irreductile quad :)
anonymous
  • anonymous
well i don't know how to do it :(
anonymous
  • anonymous
Hi Collegegirl2010, Factoring by grouping is tricky because there is no unique way to proceed. It is pretty my trying this and that and hopefully you see how the expression factors out. It is not easy to explain it, it is easier to show and after seeing a few examples you start to get the idea. The key step is grouping. But again, there are very many ways to group -- you have to use your intuition -- after a few problems you will see what to do. amistre64 showed how to do this example. Just try to follow the steps and check if the steps make sense. then try to repeat those steps on a different example. Hope this helps
anonymous
  • anonymous
So what is the answer that I am looking for
anonymous
  • anonymous
Grouping in this arena means taking groups of elements of the expression and foctorise them. They are well grouped already to do so. 14x^3-35x^2+18x-45 when grouped becomes ... (14x^3-35x^2)+(18x-45 ) now factorise each bracket 7x^2(2x - 5) + 9(2x - 5) (2x - 5) is a clear factor and the other one is construcrted from the elements outside of brackets ... (7x^2+ 9) giving the final answer ... (2x - 5)(7x^2+ 9) I hope that is clear for you.
anonymous
  • anonymous
ANY PROBLEMS WITH THE EXPLANATION JUST ASK.
anonymous
  • anonymous
Thanks these are so confusing I actually hate that I am having trouble learning them.
amistre64
  • amistre64
grouping can be a pain, if you aint got an eye for it it an be discincerting
anonymous
  • anonymous
Ciao Amistre come va?

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