watchmath
  • watchmath
Compute \[\lim_{x\to 2}\frac{\int_{-2}^x \sin(t^3)\,dt}{x^4-16}\]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
sin is odd, so as x goes to 2 the top and bottom are both going to 0. We can use L'hopitals rule and differentiate the numerator and denominator. On top we get sin(x^2). on the bottom we get 4x^3. Now we can plug in x=2. the limit as x goes to 2 is sin(4)/(32). Let me know if what I did is ok
watchmath
  • watchmath
Great! It is not very clear from above that what I wrote was sin(x^3)
anonymous
  • anonymous
oh allright then sin(8)/32

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