smurfy14
  • smurfy14
True or False?? File attached! (Please show how you know if its true/false)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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smurfy14
  • smurfy14
1 Attachment
amistre64
  • amistre64
1st is true
anonymous
  • anonymous
i dont think the first is true amistre it should be 9/x^3

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smurfy14
  • smurfy14
rsvitale i think youre right about number one
amistre64
  • amistre64
you might be right :) without () around it count it as seperate right..
anonymous
  • anonymous
66. false 67. true by distributive property. (-1/6)*(x^2+3x) 68. false you're only multiplying the top by 5 it should be 5x^2/6 69. false you need to divide the first term by 3y as well 70. false 71.false same reasoning as 70. I can explain these if you want. 72.true x^2-8x+16=(x-4)^2. then take the square root. 73.true ln(e^2)=2ln(e) 74.false e^(l+s)=(e^l)*(e^s)
smurfy14
  • smurfy14
wow lol ok lets start with 67...why did you multiply by -1/6?
anonymous
  • anonymous
70 and 71: assume sqrt(x+y)=sqrt(x)+sqrt(y) square both sides x+y=x+2sqrt(x)*sqrt(y)+y this is not true unless x,y, or both are 0 so the equality cannot be true
anonymous
  • anonymous
dividing by -6 is the same as multiplying by (-1/6)
anonymous
  • anonymous
dividing by anything is the same as multiplying by its inverse.
smurfy14
  • smurfy14
ok gotcha
anonymous
  • anonymous
inverse as in 1/something, not the technical definition of inverse
anonymous
  • anonymous
do the other ones make sense?
smurfy14
  • smurfy14
ok and well im still going down the list trying to see if i get it. are you sure 73 is true? b/isnt 2lne not the same thing as just 2 by itself?
anonymous
  • anonymous
2lne=2. the equality is ln(e^2)=2 ln(e^2)=2ln(e)=2. ln(e)=1
anonymous
  • anonymous
e to what power=e? e^1=e
smurfy14
  • smurfy14
oh ok for some reason i thought lne^2=1
anonymous
  • anonymous
no ln(e^2) means e to what power is e^2. so it is 2.
smurfy14
  • smurfy14
ok so if i said e^27 it would be 27 correct?
anonymous
  • anonymous
ln(e^27)=27 correct
smurfy14
  • smurfy14
ok and i dont get the last one
anonymous
  • anonymous
(e^l)^(s)=e^(l*s) not e^(l+s)
anonymous
  • anonymous
do you want me to explain why?
smurfy14
  • smurfy14
but i thought when you multiply exponents you add them like (x^5)(x^3)=x^8
anonymous
  • anonymous
yeah that is right. But you are multiplying e^l by itself s times. (e^l)^s=(e^l)*(e^l)*(e^l)*....*(e^l) <---- s times =e^(l+l+l+l....+l <---s times)= e^(l*s)
smurfy14
  • smurfy14
oohhh ok i get it!! well thanks so much for your help!!
anonymous
  • anonymous
you're welcome :)

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