## anonymous 5 years ago find the area and perimeter of a square with a diagonal of 10 inches please help :) thanks

1. anonymous

$x^{2}+x ^{2}=10^{2}$$2x^{2}=100$$x^{2}=\frac{100}{2}$$x=\sqrt{50}$$A=\sqrt{50}\times \sqrt{50}$ A=50 $P=4\sqrt{50}$ P=28.3

2. anonymous

the measure of its side is $5\sqrt{2}$ so, we are going to use the formula in finding its perimeter which is A=4s =4(5$4(5\sqrt{2}$) its perimeter is $20\sqrt{2}$ inches $A=s ^{2}$ $A=(5\sqrt{2})^{2}$ $A=25(2)$ A=50 in^2