when we graph the inequailty 4x - 3y>0, why cant we use (0,0) as a test point? if we test the point (6,-5), do we obtain afalse statement or a true one ?

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when we graph the inequailty 4x - 3y>0, why cant we use (0,0) as a test point? if we test the point (6,-5), do we obtain afalse statement or a true one ?

Mathematics
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because in order to determine which side of the line is valid; you have to pick a point that isnt actually on the line :)
i have been trying to figure out why but couldnt
your next best point is something on the x or the y axis so that one of your terms goes to 0

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makes more sense

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