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anonymous

  • 5 years ago

when we graph the inequailty 4x - 3y>0, why cant we use (0,0) as a test point? if we test the point (6,-5), do we obtain afalse statement or a true one ?

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  1. amistre64
    • 5 years ago
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    because in order to determine which side of the line is valid; you have to pick a point that isnt actually on the line :)

  2. anonymous
    • 5 years ago
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    i have been trying to figure out why but couldnt

  3. amistre64
    • 5 years ago
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    your next best point is something on the x or the y axis so that one of your terms goes to 0

  4. anonymous
    • 5 years ago
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    makes more sense

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