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anonymous

  • 5 years ago

How do you determine if a polynomial is the difference of two squares?

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  1. anonymous
    • 5 years ago
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    waits for amistre

  2. amistre64
    • 5 years ago
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    im here lol

  3. anonymous
    • 5 years ago
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    a suggestion is try to factor

  4. amistre64
    • 5 years ago
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    it got the '-' in it

  5. amistre64
    • 5 years ago
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    thats a big clue

  6. anonymous
    • 5 years ago
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    yeah big clue

  7. amistre64
    • 5 years ago
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    and if you see that the sides can be sqrted thats another

  8. amistre64
    • 5 years ago
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    usually; if it has a square in it and has a - they want you to diff it

  9. anonymous
    • 5 years ago
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    I don't think you can have a odd exponent as the leading term

  10. amistre64
    • 5 years ago
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    you can; but it all depends on how anal a program is lol

  11. anonymous
    • 5 years ago
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    oh

  12. amistre64
    • 5 years ago
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    you said exponent.... i read coeeff

  13. amistre64
    • 5 years ago
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    ..... still may apply tho lol

  14. anonymous
    • 5 years ago
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    happens to me all the time. im fukin dyslexic or something

  15. anonymous
    • 5 years ago
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    how did her question get from facotring to such an analytical question. Interesting text book

  16. amistre64
    • 5 years ago
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    \(x^{\sqrt{5}}\)

  17. anonymous
    • 5 years ago
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    or maybe th answer is in the introductioin of the cchapter

  18. amistre64
    • 5 years ago
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    \[x^{5^{1/2}}\] lol

  19. anonymous
    • 5 years ago
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    x^ 1/5 - 0 X^1/5+ 0 ?

  20. anonymous
    • 5 years ago
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    I just need a 50 word response for my paper that is all I need

  21. anonymous
    • 5 years ago
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    is this a grad course on teaching algebra?

  22. anonymous
    • 5 years ago
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    So I am trying to put that all down and in the correct form so that it sounds right

  23. anonymous
    • 5 years ago
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    I don't know the definate answer to your question

  24. anonymous
    • 5 years ago
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    No it is my algebra/117 my last basic class that I need

  25. amistre64
    • 5 years ago
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    uhoh..... if you qoute me youre gonna need alot of ****

  26. anonymous
    • 5 years ago
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    Praphrase

  27. amistre64
    • 5 years ago
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    amistre64 says yada yada yada; someday it may even be proven correct lol

  28. anonymous
    • 5 years ago
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    lol

  29. anonymous
    • 5 years ago
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    I am trying to write on my own I just need something to get started with

  30. anonymous
    • 5 years ago
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    write P=NP

  31. anonymous
    • 5 years ago
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    i'll give you $400,000 if you can prove that

  32. anonymous
    • 5 years ago
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    I think im short changing you, too

  33. amistre64
    • 5 years ago
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    P=NP when P=0

  34. anonymous
    • 5 years ago
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    lol

  35. anonymous
    • 5 years ago
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    that's not proving P=NP, that's a case

  36. amistre64
    • 5 years ago
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    ;)

  37. anonymous
    • 5 years ago
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    you can use a case to prove but you can't prove by cases

  38. amistre64
    • 5 years ago
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    \[x^y + y^x = xy^{x+y}\]

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