Write the equation of the line that passes through the point (6, -2) and has a slope of -2/3

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Write the equation of the line that passes through the point (6, -2) and has a slope of -2/3

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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y = -(2/3)(x-6)-2
\[y = -\frac{2x}{3} -6\]

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Other answers:

that aint right is it..
idk lol
-*-=+ i see it
\[y = -\frac{2}{3}x-10\] maybe
im gonna have to do this the long way...
y=−(2/3)X + 2
thanks
y = -(2/3)(x-6)-2 y = (-2/3)x+(-2/3)-6 -2 y = (-2/3)x+(12/3) -2 y = (-2/3)x+2 is right
....fraction keep laughing at me
you need to use the point slope formula for these problems: \[(y-y _{1}) = m(x - x _{1})\]
i shoulda multied his butt with a 3 ....thatd a showed it
so this isnt the right answer
just use the formula, y-y1=m(x-x1) (6, -2) and has a slope of -2/3 y+2=-2/3(x-6) 3(y+2)=-2(x-6) 3y+6=-2x+12 2x+3y=12-6 2x+3y=6
this is right.

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