## anonymous 5 years ago Write the equation of the line that passes through the point (6, -2) and has a slope of -2/3

1. Owlfred

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2. amistre64

y = -(2/3)(x-6)-2

3. amistre64

$y = -\frac{2x}{3} -6$

4. amistre64

that aint right is it..

5. anonymous

idk lol

6. amistre64

-*-=+ i see it

7. amistre64

$y = -\frac{2}{3}x-10$ maybe

8. amistre64

im gonna have to do this the long way...

9. anonymous

y=−(2/3)X + 2

10. anonymous

thanks

11. amistre64

y = -(2/3)(x-6)-2 y = (-2/3)x+(-2/3)-6 -2 y = (-2/3)x+(12/3) -2 y = (-2/3)x+2 is right

12. amistre64

....fraction keep laughing at me

13. anonymous

you need to use the point slope formula for these problems: $(y-y _{1}) = m(x - x _{1})$

14. amistre64

i shoulda multied his butt with a 3 ....thatd a showed it

15. anonymous

so this isnt the right answer

16. anonymous

just use the formula, y-y1=m(x-x1) (6, -2) and has a slope of -2/3 y+2=-2/3(x-6) 3(y+2)=-2(x-6) 3y+6=-2x+12 2x+3y=12-6 2x+3y=6

17. anonymous

this is right.

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