anonymous
  • anonymous
Write the equation of the line that passes through the point (6, -2) and has a slope of -2/3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Owlfred
  • Owlfred
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amistre64
  • amistre64
y = -(2/3)(x-6)-2
amistre64
  • amistre64
\[y = -\frac{2x}{3} -6\]

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amistre64
  • amistre64
that aint right is it..
anonymous
  • anonymous
idk lol
amistre64
  • amistre64
-*-=+ i see it
amistre64
  • amistre64
\[y = -\frac{2}{3}x-10\] maybe
amistre64
  • amistre64
im gonna have to do this the long way...
anonymous
  • anonymous
y=−(2/3)X + 2
anonymous
  • anonymous
thanks
amistre64
  • amistre64
y = -(2/3)(x-6)-2 y = (-2/3)x+(-2/3)-6 -2 y = (-2/3)x+(12/3) -2 y = (-2/3)x+2 is right
amistre64
  • amistre64
....fraction keep laughing at me
anonymous
  • anonymous
you need to use the point slope formula for these problems: \[(y-y _{1}) = m(x - x _{1})\]
amistre64
  • amistre64
i shoulda multied his butt with a 3 ....thatd a showed it
anonymous
  • anonymous
so this isnt the right answer
anonymous
  • anonymous
just use the formula, y-y1=m(x-x1) (6, -2) and has a slope of -2/3 y+2=-2/3(x-6) 3(y+2)=-2(x-6) 3y+6=-2x+12 2x+3y=12-6 2x+3y=6
anonymous
  • anonymous
this is right.

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