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Maddiie

  • 5 years ago

Find the solution to each system by the substitution method. 10x+3y=-8 2x+y=2

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  1. anonymous
    • 5 years ago
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    second equation gives \[y=2-2x\] substitute in the first equation to get \[10x+3(2-2x)=-8\]

  2. maddiie
    • 5 years ago
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    10x=6x+6=-8

  3. anonymous
    • 5 years ago
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    \[10x+6-6x=-8\] \[4x+6=-8\] \[4x=-8-6=-14\] \[x=-\frac{14}{4}=-\frac{7}{2}\]

  4. maddiie
    • 5 years ago
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    Ok

  5. anonymous
    • 5 years ago
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    now you have to substitute back to find y

  6. anonymous
    • 5 years ago
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    \[y=2-2x\] \[y=2-2\times- \frac{7}{2}\] \[y=2+7\] \[y=9\]

  7. anonymous
    • 5 years ago
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    hold on let me check

  8. maddiie
    • 5 years ago
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    I was doing while you were teaching me and i got the smae thing useless i'm wrong too. I am understanding this

  9. anonymous
    • 5 years ago
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    oh yeah it is right!

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