Find the solution to each system by the substitution method. 10x+3y=-8 2x+y=2

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Find the solution to each system by the substitution method. 10x+3y=-8 2x+y=2

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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second equation gives \[y=2-2x\] substitute in the first equation to get \[10x+3(2-2x)=-8\]
10x=6x+6=-8
\[10x+6-6x=-8\] \[4x+6=-8\] \[4x=-8-6=-14\] \[x=-\frac{14}{4}=-\frac{7}{2}\]

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Other answers:

Ok
now you have to substitute back to find y
\[y=2-2x\] \[y=2-2\times- \frac{7}{2}\] \[y=2+7\] \[y=9\]
hold on let me check
I was doing while you were teaching me and i got the smae thing useless i'm wrong too. I am understanding this
oh yeah it is right!

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