## anonymous 5 years ago tan theta = -4/3 then sin theta =?

1. immanuelv

tan theta = sin theta / cos theta

2. anonymous

yes i found sin theta = -4/3 cos theta

3. immanuelv

yes !

4. anonymous

do u want options

5. immanuelv

what?

6. anonymous

a) -4/5 but not 4/5 b) -4/5 or 4/5 c) 4/5 but not -4/5 d) none of these

7. anonymous

$sin(\theta)=\pm\frac{4}{5}$

8. anonymous

option b if you have no further information

9. anonymous

how pls elaborate

10. anonymous

ok if you draw a right triangle and think of one angle as theta, then you can visualize tangent as "opposite over adjacent" label the opposite side 4, the adjacent side 3 and the hypotenuse will be 5 by pythagoras

11. anonymous

CAN U TELL ME WITH THE HELP OF FORMULA

12. anonymous

ok we have one adjacent side 3 and opposite side 4 yes? then pythagoras tells us $a^2+b^2=c^2$ where the sides are a and b and c is the hypotenuse. $3^2+4^2=9+16=25$ so the hypotenuse is 5

13. anonymous

if you think of sine as opposite over hypotenuse then you know $\sin(x)=\frac{4}{5}$ but you do not know what quadrant you are in so you do not know if sine is positive or negative

14. anonymous

I UNDERSTOOD VERY VERY VERY THANKS TO U

15. anonymous

BUT The ratio of the radii of two circles at the centers of which two arcs of the same length subtended a angles of 60 degree and 70 degree is

16. anonymous

welcome

17. anonymous

CAN U ANSWER ME THIS QUESTION ALSO The ratio of the radii of two circles at the centers of which two arcs of the same length subtended a angles of 60 degree and 70 degree is

18. anonymous

actually no because i do not know what the question means

19. anonymous

OK ANYWAY THANKS