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anonymous

  • 5 years ago

tan theta = -4/3 then sin theta =?

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  1. immanuelv
    • 5 years ago
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    tan theta = sin theta / cos theta

  2. anonymous
    • 5 years ago
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    yes i found sin theta = -4/3 cos theta

  3. immanuelv
    • 5 years ago
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    yes !

  4. anonymous
    • 5 years ago
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    do u want options

  5. immanuelv
    • 5 years ago
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    what?

  6. anonymous
    • 5 years ago
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    a) -4/5 but not 4/5 b) -4/5 or 4/5 c) 4/5 but not -4/5 d) none of these

  7. anonymous
    • 5 years ago
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    \[sin(\theta)=\pm\frac{4}{5}\]

  8. anonymous
    • 5 years ago
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    option b if you have no further information

  9. anonymous
    • 5 years ago
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    how pls elaborate

  10. anonymous
    • 5 years ago
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    ok if you draw a right triangle and think of one angle as theta, then you can visualize tangent as "opposite over adjacent" label the opposite side 4, the adjacent side 3 and the hypotenuse will be 5 by pythagoras

  11. anonymous
    • 5 years ago
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    CAN U TELL ME WITH THE HELP OF FORMULA

  12. anonymous
    • 5 years ago
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    ok we have one adjacent side 3 and opposite side 4 yes? then pythagoras tells us \[a^2+b^2=c^2\] where the sides are a and b and c is the hypotenuse. \[3^2+4^2=9+16=25\] so the hypotenuse is 5

  13. anonymous
    • 5 years ago
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    if you think of sine as opposite over hypotenuse then you know \[\sin(x)=\frac{4}{5}\] but you do not know what quadrant you are in so you do not know if sine is positive or negative

  14. anonymous
    • 5 years ago
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    I UNDERSTOOD VERY VERY VERY THANKS TO U

  15. anonymous
    • 5 years ago
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    BUT The ratio of the radii of two circles at the centers of which two arcs of the same length subtended a angles of 60 degree and 70 degree is

  16. anonymous
    • 5 years ago
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    welcome

  17. anonymous
    • 5 years ago
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    CAN U ANSWER ME THIS QUESTION ALSO The ratio of the radii of two circles at the centers of which two arcs of the same length subtended a angles of 60 degree and 70 degree is

  18. anonymous
    • 5 years ago
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    actually no because i do not know what the question means

  19. anonymous
    • 5 years ago
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    OK ANYWAY THANKS

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