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anonymous

  • 5 years ago

Television sets. What does it mean to refer to a 20 -in tv set or a 25-in tv set? Such units refer to the diagonal of the screen. a 35-in tv set also has a width of 28 inches. What is the height of a 35-inch tv ...inches???

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  1. amistre64
    • 5 years ago
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    h = sqrt(35^2 - 28^2)

  2. amistre64
    • 5 years ago
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    h = 21

  3. anonymous
    • 5 years ago
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    \[h=\sqrt{35^2-28^2}\] \[h=\sqrt{1225-784}\] \[h=\sqrt{441}\] \[h=21\]

  4. anonymous
    • 5 years ago
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    damn i am slow

  5. anonymous
    • 5 years ago
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    at any rate i hope it is clear that this all comes from \[a^2+b^2=c^2\] where a and b are the sides and c is the hypotenuse. so you are thinking of the diagonal as the hypotenuse and the sides as 35 and 28

  6. anonymous
    • 5 years ago
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    actually i meant you are thinking of the hypotenuse as 35 and one of the sides at 28

  7. anonymous
    • 5 years ago
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    so you get \[28^2+h^2=35^2\] and then solve for h

  8. anonymous
    • 5 years ago
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    \[h^2=35^2-28^2\] etc

  9. anonymous
    • 5 years ago
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    Ok i see what you are saying

  10. anonymous
    • 5 years ago
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    good!

  11. anonymous
    • 5 years ago
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    if one leg of a triangle is 5 and the hypotenuse is 13 then you know \[5^2+b^2=13^2\]

  12. anonymous
    • 5 years ago
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    solving for b gives first \[b^2=13^2-5^2\] and then \[b=\sqrt{13^2-5^2}\]

  13. anonymous
    • 5 years ago
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    but if you do this often you just go right to the last step

  14. anonymous
    • 5 years ago
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    \[h=28 \text{Tan}\left[\text{ArcCos}\left[\frac{28}{35}\right]\right] \]

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