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anonymous
 5 years ago
Television sets. What does it mean to refer to a 20 in tv set or a 25in tv set? Such units refer to the diagonal of the screen. a 35in tv set also has a width of 28 inches. What is the height of a 35inch tv ...inches???
anonymous
 5 years ago
Television sets. What does it mean to refer to a 20 in tv set or a 25in tv set? Such units refer to the diagonal of the screen. a 35in tv set also has a width of 28 inches. What is the height of a 35inch tv ...inches???

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1h = sqrt(35^2  28^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[h=\sqrt{35^228^2}\] \[h=\sqrt{1225784}\] \[h=\sqrt{441}\] \[h=21\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0at any rate i hope it is clear that this all comes from \[a^2+b^2=c^2\] where a and b are the sides and c is the hypotenuse. so you are thinking of the diagonal as the hypotenuse and the sides as 35 and 28

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0actually i meant you are thinking of the hypotenuse as 35 and one of the sides at 28

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you get \[28^2+h^2=35^2\] and then solve for h

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[h^2=35^228^2\] etc

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok i see what you are saying

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if one leg of a triangle is 5 and the hypotenuse is 13 then you know \[5^2+b^2=13^2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0solving for b gives first \[b^2=13^25^2\] and then \[b=\sqrt{13^25^2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but if you do this often you just go right to the last step

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[h=28 \text{Tan}\left[\text{ArcCos}\left[\frac{28}{35}\right]\right] \]
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