- anonymous

can i get an example for a problem of solving an absolute value equation, please?

- chestercat

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- Owlfred

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- anonymous

the absolute value of x is 6. so x could be either 6 or -6

- anonymous

\[|x-3|=5\]
\[x-3=5\]
\[x-3=-5\]
\[x-3=5 , x=8\]
\[x-3=-5, x=-2\]

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## More answers

- anonymous

there are two. do you have one you would like to do?

- anonymous

yeah, the |x-3| = 5 one.

- anonymous

the problem is, I don't quite remember how to do the process. Could one help.

- anonymous

just remember when you remove the absolute value signs you have to write two separate equations

- anonymous

this is clear yes? because if i know
\[|x|=78\] then x could be 78 but it could also be -78

- anonymous

yeah, I just looked that up, and it made sense. Now what if there's two variables, like |x-3| = 5, would the answer be, "2 or -2" ?

- anonymous

oh no

- anonymous

what? why?

- anonymous

because if i know |x-3|=5 then what i know is that either x-3=5 or x-3=-5

- anonymous

the solution to the first one is x = 8, not x = 2. the solution to the second one IS x=-2

- anonymous

Ok. I kind of see what you did... Could you give me another one amongst those lines, so I can try it?

- anonymous

sure try |x+3|=7

- anonymous

The answer to the first one should be 4, and the second one, being (|x+3| = -7) would be -10?

- anonymous

yes . got it. write to equations, solve each individually

- anonymous

i meant write TWO equations

- anonymous

Yeah, for sure! (: It's just I'm a bit slow at first, but once I get it, I beast through all of them, lol. Btw, are there any equations like that, with THREE variables?

- anonymous

not usually. do you have one?

- anonymous

No, I just wanted to know so I could be prepared in case I get one of those.

- anonymous

you could have something like this:
|x+2|=2x-5

- anonymous

and how would you solve that?

- anonymous

in which case you still have to write two equations but you have to be very very careful

- anonymous

you would write two equations. one would be:
x+2=2x-5

- anonymous

the other would be:
x+2=-(2x-5)

- anonymous

which of course means
x+2=-2x+5

- anonymous

be careful when you take the negative to remember to put it in parentheses

- anonymous

alright, and so from there, what step is next?

- anonymous

just solve like any linear equation.
\[x+2=2x-5\]
\[2+5=2x-x\]
\[7=x\]

- anonymous

or
\[x+2=-(2x-5)\]
\[x+2=-2x+5\]
\[x+2x=5-2\]
\[3x=3\]
\[x=1\]

- anonymous

OH, OK!

- anonymous

hey do you have time, ? because i have another question...

- anonymous

and btw, thanks a lot.

- anonymous

AWH, no satellite, dont forsake me right now! I got aaaaaa big TEST tomorrow!

- anonymous

one more and then i turn into a pumpkin

- anonymous

what's that mean?

- anonymous

go ahead and ask

- anonymous

never saw or read cinderella?

- anonymous

oh, yeah, aha.... but its only 10:44, doesn't that happen at 12?

- anonymous

eastern standard time

- anonymous

Interesting. Ok, anyways, sorry for delaying your transformation, but could you give me some heads up on solving prequalities?

- anonymous

?? ptequalities?

- anonymous

even spell check doesn't like that

- anonymous

I don't know, the weird lady put one of the subjects we need to study, under "Solving prequaltities and graphing solution." Any ideas?

- anonymous

sorry never heard of them.

- anonymous

google hasn't either so i don't feel bad

- anonymous

Yeah, it doesn't even show up on google. !

- anonymous

Alright, well, you've been of great help! And I appreciate it. Thank you, who ever you are, and have a good one!

- anonymous

gnight.

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