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9x-4y=c to determine c plug x=8,y=-8 so 72+32=c=104 so we have 9x-4y=104.. i assume u know that equation of a line perpendicular to ax+by+c=0 is bx-ay+k=0 where c and k are different constants.. so our answer is y=(1/4)(9x-104)
jazi1 do u get tat? :)
jazi1: could you please try and _understand_ how it is done, and not let the others do all these problems, which are merely the same with different numbers!
nowhereman seems like you are the only one complaining
saubhik I got it but I don't understand it
i think nowhereman is right:) but u shud understand what i did...or ask what u didnt get in this process instead of asking similar problems...:) happy to help... :)
line 1: 4x + 9y = 7 It should help you to rearrange this equation with y on one side in order to resemble the standard y = mx + b format. It's critical because you need to identify the slope (m) in order to recreate a parallel or perpendicular line. In our case: 4x + 9y = 7 9y = 7 - 4x y = 7/9 - (4/9)x y = (-4/9)x + 7/9 Can you identify which is the slope (m) in this equation?
ok...jazi1 see if we have perpendicular lines we have product of their slopes as -1. so u can tell that ax+by+c=0 and bx-ay+k=0 are 2 perpendicular lines..i used this idea..do u get this? :)
saubhik got it
so ur given equation is 4x+9y-7=0..so u know that the perpendicular to it has to be of the form 9x-4y+c=0 where we have to determine the constant c..do u get this? :)
For finding c we just plug the given coordinates! thats it..nice and easy! :)
-4x+7 y=--------- = -4x/9 +7/9, here slope m= -4/9 9 now at point(8,-8), from y-y1=m(x-x1) y-(-8)= -4/9 (x-8) y+8 = -4x/9 +32/9 y= -4x/9 +32/9 - 8 y=-4x/9 - 40/9 EQ of the line at point(8,-8)
Mark I do thank you but the correct ans is 9/4x - 26
ok good try to review the process i might have missed something there..lol just in a hurry lol
did you see it jazi? lol sorry iwas just in a hurry to give it to you lol...
ok i saw it m=9/4 y-y1=m(x-x1) y-(-8)=9/4(x-8) y+8 =9x/4 - 72/4 y = 9x/4 -18 -8 y= 9x/4 -26 answer
y= 9x/4 -26 this is the EQ of perpendicular line to it
Ok thanks mark for being so helpful
wc just understand the process of geting the Eq of the line and the EQ of the line Perpendicular to it..good luck Jazil
saubnik did the other way of geting the line perpendicular to it which i think a kind of advance for the beginers but it is very good techniques and good process too
if a^3 = b^3 + c^3 + d^3 , then least value of a is ?