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anonymous
 5 years ago
Is (1,5) the solution to 6x5<= 11x + y ? If o, how do I graph it properly?
anonymous
 5 years ago
Is (1,5) the solution to 6x5<= 11x + y ? If o, how do I graph it properly?

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Owlfred
 5 years ago
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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no its not the solution to it 6x5<= 11x + y just plug the x=1, y=5 6(1)5<= 11(1) + 5 6 5 <= 115 11 <=16 false....bec 16< 11

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Try to see 5 in terms of x and y first... 6x5<= 11x + y 5<= 11x + y 6y 5<= 5x + y If (1, 5) is a solution then bu replacingx with 1 and y with 5 we get... 5<5(1) + (5) which yields ... 5<5 5 which simplifiest to ... 5 <10 This you will see is an untrue statement and as such the coordinate paire do not satisfy this particular inequality.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How to graph it properly ... Write y in terms of x and then feed 3 values in to the x variable. 6x5<= 11x + y impliest that ... 6x 11x 5 <= y or even better ... 5x5 <= y If x = 0 say, then y = 5 hence (0, 5) is on the line If x = 2 say, then y = 5 hence (2, 5) is on the line If x = 3 say, then y = 10 hence (3, 10) is on the line Now check the attached jpeg to see the graph The shaded area represents all coordinates that make the inequality true THE BROKEN GRAPH LINE SHOWS THAT THE COORDINATES ON THAT LINE ARE NOT PERMISSABLE.
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