Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

\(C_1\) is a fixed circle given by \((x-1)^2+y^2=1\) and \(C_2\) is a shriking circle with radius \(r\). \(P\) is the point of \((0,r)\), \(Q\) is the upper point of intersection of the two circles,a nd \(R\) is the point of intersection of the line \(PQ\) and the \(x\)-axis. WHat happens to \(R\) as \(C_2\) shrinks, that is, as \(r\to 0^+\)?

it moves toward the y axis

if a^3 = b^3 + c^3 + d^3 , then least value of a is ?

PLS HELP

the Y(op)-->0 and PR-->0R

if a^3 = b^3 + c^3 + d^3 , then least value of a is ?

P=Q because C1 and C2 intersect at the origin

You need to work out this more rigorously. Your intuition can deceive you here.

But we are interested in finding R (as r-->0 ). How is the fact that you mention helping us?

R is the x-intercept of PQ
so i'm not seeing how the line PQ isn't approaching the x-axis or y=0

meaning R would be every point on the x-axis since PQ is that line
I don't know
its late

i go to sleep and dream about it tonight k?

oops this morning its 3:34 am

It is 4:42 here :). I think dumbcow will answer this, right? :D

limit as r->0 is 4

not 100% but i was able to get R as a function of r

Yes, then now it is just an exercise of computing limit.

\[R =\frac{r^{2}}{2-\sqrt{4-r^{2}}}\]
use L'hopitals rule

thats right Q is the intersection of the two circles :(

btw thanks for the diagram
could not have done this without that, im a visual person :)

ok i guess i see how it can be 4 lol

but it never totally goes flat
okay i get it

meaning there is a x-intercept

right P approaches the origin
and PQ approaches the x-axis
but dont ever get there :)

because we never get to the origin lol

thanks cow

your welcome
watchmath did that answer all your questions

watchmath give me another i want to prove i can think like a pro

don't do it now
wait til tomorrow
let me sleep
if you give it to me now then i will never sleep

now in this two EQ, you can compute the intersection PQ and get its X and Y