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anonymous

  • 5 years ago

Describe each graph using set-builder notation and in interval notation Please show work. -------------> <-7,-6,-5,-4,-3,-2,-1, 0 1, 2, 3, 4, 5,6,7>

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  1. anonymous
    • 5 years ago
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    \[x : x \in I , -7\le x \le7\]

  2. anonymous
    • 5 years ago
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    my teacher told me this On your third problem, the numbers in your solution go on forever. They don't stop at 7! Try thinking about this kind of problem in reverse. For example, if I had the inequality of x > 5, then my graph would start at 5 ( but not include the 5) and it would go on forever (that would be infinity) to the right. but im still not getting it!

  3. anonymous
    • 5 years ago
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    Keebler, the question is difficult to see the way it is printed. but if the chevrons in it indicate a contained set then Ishan is correct. The I in the setbuilder notation I suspect is an alternative to what we use in Europe for INTEGERS. We use Z. Check the question again to see if the ambiguity can be addressed.

  4. anonymous
    • 5 years ago
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    Describe each graph using set-builder notation and in interval notation Please show work.

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  5. anonymous
    • 5 years ago
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    I have added to your word file.

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