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anonymous

  • 5 years ago

if a^3 = b^3 + c^3 + d^3 , then least value of a is ?

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  1. anonymous
    • 5 years ago
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    PLS HELP

  2. anonymous
    • 5 years ago
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    hi kushashwa,,Are you in algebra class or calculus?

  3. anonymous
    • 5 years ago
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    AALGEBRA

  4. anonymous
    • 5 years ago
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    PLS HELP ME

  5. anonymous
    • 5 years ago
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    HELP ME PLEASE

  6. anonymous
    • 5 years ago
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    a<0 , b<0 , c<0

  7. anonymous
    • 5 years ago
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    HOW

  8. watchmath
    • 5 years ago
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    Assuming that a,b,c,d are all positive then we have \(a^3\geq 3\sqrt[3]{b^3c^3d^3}=3bcd\) Hence \[a\geq \sqrt[3]{3bcd}\] So \(\sqrt[3]{3bcd}\) is the minimum value of \(a\).

  9. anonymous
    • 5 years ago
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    OK THANKS VERY MUCH

  10. anonymous
    • 5 years ago
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    ANY1 HAVE A DIFFERENT ANSWER????????????///

  11. anonymous
    • 5 years ago
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    WATCH MATH UR ANSWER IS NOT IN OPTION A)3 B)9 C)6 D) 12

  12. watchmath
    • 5 years ago
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    Then you didn't put the problem completely. What do we know about a,b,c,d? we need more context.

  13. anonymous
    • 5 years ago
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    no it is the full given

  14. anonymous
    • 5 years ago
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    help me any1 else

  15. watchmath
    • 5 years ago
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    The complete problem usually use a complete sentece like this: Let \(a,b,c,d\) be such and such .....

  16. anonymous
    • 5 years ago
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    can we do it with hit and trial method

  17. anonymous
    • 5 years ago
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    i thnk it is , if b=c=d then a^3 = b^3 + b^3 + b^3 =3b^3

  18. anonymous
    • 5 years ago
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    i think we should refer options first

  19. anonymous
    • 5 years ago
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    now if b=1, then a^3=3(1)^3 a^3=3

  20. anonymous
    • 5 years ago
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    hey the answer is 9 i think

  21. anonymous
    • 5 years ago
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    because by hit and trial method 9 is the least number that satisfies the given condition 9^3 = 8^3 + 6^3 + 1^3 729 = 512 + 216 + 1 729 = 729

  22. anonymous
    • 5 years ago
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    WHAT DO U ALL SAY ABOUT THIS ANSWER I THINK I M CORRECT

  23. anonymous
    • 5 years ago
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    PLS SUGGEST

  24. anonymous
    • 5 years ago
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    because by hit and trial method 9 is the least number that satisfies the given condition 9^3 = 8^3 + 6^3 + 1^3 729 = 512 + 216 + 1 729 = 729 IS THIS CORRECT SOLUTION

  25. anonymous
    • 5 years ago
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    pls reply me

  26. anonymous
    • 5 years ago
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    i just did hit and trial method

  27. anonymous
    • 5 years ago
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    but where did you get those 8, 6 and 1?

  28. anonymous
    • 5 years ago
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    if a^3 = b^3 + c^3 + d^3 hence i thought that a must be greater than b, c and d. so if a = 9 hence b , c and d will be among 1, 2, 3, 4 , 5, 6, 7, 8 i took the cubes of these numbers and took the numbers whose sum contains unit digit as 9.

  29. anonymous
    • 5 years ago
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    hence i found many pairs but i found 8, 6 and 1 as correct group . AM I CORRECT PLS TELL ME

  30. anonymous
    • 5 years ago
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    i think it is 3,,, try b=1, c=0 d=0, then try c=1,b=0,d=0, then try d=1,b=0,c=0

  31. anonymous
    • 5 years ago
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    M VERY SORRY TO ALL OF U THE ANSWER WILL BE 6 6^3 = 5^3 + 4^3 + 3^3 216 = 216

  32. anonymous
    • 5 years ago
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    NO MARK IT CAN NOT BE THREE 3^3 IS NOT EQUAL TO ANY SUM OF THREE CUBES

  33. anonymous
    • 5 years ago
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    lol...well thats the least i can see ...lol,, so accordingly b cant be equal to c cant be equal to d,....ok....we need to complete the prob specifically...lol

  34. anonymous
    • 5 years ago
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    TELL ME CLEARLY WHAT IS THE ANSWER. WHAT DO U THINK. I THINK 6 WOULD BE THE ANSWER

  35. anonymous
    • 5 years ago
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    A)3 B)9 C)6 D) 12

  36. anonymous
    • 5 years ago
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    say b=1,c=2 and d=3... also try b-0,c=1 and d=3

  37. myininaya
    • 5 years ago
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    3 since 3^3=3^3+0^3+0^3

  38. anonymous
    • 5 years ago
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    yes thats it its 3

  39. anonymous
    • 5 years ago
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    YEAH THAT MAY BE

  40. myininaya
    • 5 years ago
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    it is since there are no restrictions on a,b,c,d, right?

  41. anonymous
    • 5 years ago
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    wait

  42. myininaya
    • 5 years ago
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    i mean of the options for a that is the smallest but there can be smaller

  43. myininaya
    • 5 years ago
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    like a->-infinity would be the smallest lol since a negative to an odd power is still negative and can be negative large

  44. anonymous
    • 5 years ago
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    but it is showing 6 as the answer

  45. myininaya
    • 5 years ago
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    do b,c,d have to be postiive?

  46. myininaya
    • 5 years ago
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    if not then 6 is wrong

  47. anonymous
    • 5 years ago
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    i also don't know the question that was given i typed i think the question is wrong it should mention the whole context thanks very much

  48. anonymous
    • 5 years ago
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    ok, wc and thnx

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