At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

PLS HELP

hi kushashwa,,Are you in algebra class or calculus?

AALGEBRA

PLS HELP ME

HELP ME PLEASE

a<0 , b<0 , c<0

HOW

OK THANKS VERY MUCH

ANY1 HAVE A DIFFERENT ANSWER????????????///

WATCH MATH UR ANSWER IS NOT IN OPTION
A)3
B)9
C)6
D) 12

Then you didn't put the problem completely. What do we know about a,b,c,d? we need more context.

no it is the full given

help me any1 else

can we do it with hit and trial method

i thnk it is , if b=c=d
then a^3 = b^3 + b^3 + b^3 =3b^3

i think we should refer options first

now if b=1, then a^3=3(1)^3
a^3=3

hey the answer is 9 i think

WHAT DO U ALL SAY ABOUT THIS ANSWER I THINK I M CORRECT

PLS SUGGEST

pls reply me

i just did hit and trial method

but where did you get those 8, 6 and 1?

hence i found many pairs but i found 8, 6 and 1
as correct group . AM I CORRECT PLS TELL ME

i think it is 3,,, try b=1, c=0 d=0, then try c=1,b=0,d=0, then try d=1,b=0,c=0

M VERY SORRY TO ALL OF U
THE ANSWER WILL BE 6
6^3 = 5^3 + 4^3 + 3^3
216 = 216

NO MARK IT CAN NOT BE THREE
3^3 IS NOT EQUAL TO ANY SUM OF THREE CUBES

TELL ME CLEARLY WHAT IS THE ANSWER. WHAT DO U THINK.
I THINK 6 WOULD BE THE ANSWER

A)3
B)9
C)6
D) 12

say b=1,c=2 and d=3...
also try b-0,c=1 and d=3

3 since
3^3=3^3+0^3+0^3

yes thats it its 3

YEAH THAT MAY BE

it is since there are no restrictions on a,b,c,d, right?

wait

i mean of the options for a that is the smallest but there can be smaller

but it is showing 6 as the answer

do b,c,d have to be postiive?

if not then 6 is wrong

ok, wc and thnx