can you help me to solve the following inequality: x^2 >=16

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can you help me to solve the following inequality: x^2 >=16

Mathematics
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Can you show the work, please?
graph \[y=x^2-16\] and you will see a parabola that faces up and crosses the x-axis at -4 and 4. from the picture you will see that it is positive if x<-4 or if x> 4
analitically

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there is another more complicated way to do this, but if you know what the graph of \[y=x^2-16\] looks like it is simple.
well step number one is going to be to write \[x^2-16\geq0\]
so you are going to have to work with that in any case. you cannot, for example, take the square root of both sides.
I need to do it analitically
then you can factor \[x^2-16=(x+4)(x-4)\geq 0\]
got it
Im such a fool
then you can look at the sign of each factor. yes?
you are still going to get positive, negative, positive on \[(-\infty,-4), (-4,4), (4,\infty) \] respectively
thanks
welcome

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