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anonymous
 5 years ago
can you help me to solve the following inequality:
x^2 >=16
anonymous
 5 years ago
can you help me to solve the following inequality: x^2 >=16

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you show the work, please?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0graph \[y=x^216\] and you will see a parabola that faces up and crosses the xaxis at 4 and 4. from the picture you will see that it is positive if x<4 or if x> 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there is another more complicated way to do this, but if you know what the graph of \[y=x^216\] looks like it is simple.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well step number one is going to be to write \[x^216\geq0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you are going to have to work with that in any case. you cannot, for example, take the square root of both sides.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I need to do it analitically

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then you can factor \[x^216=(x+4)(x4)\geq 0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then you can look at the sign of each factor. yes?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you are still going to get positive, negative, positive on \[(\infty,4), (4,4), (4,\infty) \] respectively
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