anonymous
  • anonymous
can you help me to solve the following inequality: x^2 >=16
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Can you show the work, please?
anonymous
  • anonymous
graph \[y=x^2-16\] and you will see a parabola that faces up and crosses the x-axis at -4 and 4. from the picture you will see that it is positive if x<-4 or if x> 4
anonymous
  • anonymous
analitically

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anonymous
  • anonymous
there is another more complicated way to do this, but if you know what the graph of \[y=x^2-16\] looks like it is simple.
anonymous
  • anonymous
well step number one is going to be to write \[x^2-16\geq0\]
anonymous
  • anonymous
so you are going to have to work with that in any case. you cannot, for example, take the square root of both sides.
anonymous
  • anonymous
I need to do it analitically
anonymous
  • anonymous
then you can factor \[x^2-16=(x+4)(x-4)\geq 0\]
anonymous
  • anonymous
got it
anonymous
  • anonymous
Im such a fool
anonymous
  • anonymous
then you can look at the sign of each factor. yes?
anonymous
  • anonymous
you are still going to get positive, negative, positive on \[(-\infty,-4), (-4,4), (4,\infty) \] respectively
anonymous
  • anonymous
thanks
anonymous
  • anonymous
welcome

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