anonymous
  • anonymous
Factor the trinomial: w^3-2w^2-8w
Mathematics
schrodinger
  • schrodinger
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amistre64
  • amistre64
factor out the 'w;' and work the quad
amistre64
  • amistre64
w,-4,2
amistre64
  • amistre64
w(w-4)(w+2)

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anonymous
  • anonymous
do I have to have the w on the outside or can I put it in form (w-4)(w+2)
amistre64
  • amistre64
the 'w' is a part of the factoring; it needs to be a part of the soultion or you dont get the same answer. That would be like saying; if I dont pay you for the first 3 hours you work, do you still get a full paycheck :)
amistre64
  • amistre64
or numbers for example: 4(3)(2) = 24 ; can we omit the 4? ___(3)(2) = 6; cant do it ;)_
anonymous
  • anonymous
ok well my work shows there are no letters on the outside of the parenthesis on any of the questions that are the same. So that is why I'm trying to figure out why urs does and theres dont
amistre64
  • amistre64
are the problems you are looking at start with a 'w^3' ? 'w' being a dummy variable and any letter will work.
amistre64
  • amistre64
the highest exponent in a problem is a good indicator of how many factors it will have
amistre64
  • amistre64
x^2 can only have at most 2 factors x*x x^3 can only have at most 3 factors: x*x*x
anonymous
  • anonymous
this is exactly what they give me Factor the trinomial w^3-2w^2-8w there showing me to pair of factors and sum of factors to get the answer
amistre64
  • amistre64
first step; factor out all common elements: the 'w' w ( w^2 -2x -8 ) step 2: factor, if possible, the inside of the (...) w (w-4) (w+2) step 3: factor inside the (..) if possible. no other factors step 4: and.
amistre64
  • amistre64
lol.... and means end :)
anonymous
  • anonymous
what two numbers equal 2, and they have to be common factor of both 2 and 8
amistre64
  • amistre64
-4(2) = -8 ... check -4+2 = -2 ... check
amistre64
  • amistre64
(x+b)(x+c) = xx + xc +bx +bc x^2 +(b+c)x + b*c is how we form a quadratic
amistre64
  • amistre64
to factor it, we need to find 'b' and 'c' that make the middle and last numbers
amistre64
  • amistre64
x^2 + (-4+2)x + -4(2) x^2 -2x -8 ; you just gotta be able to see how its made... and that takes practice :)

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