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anonymous

  • 5 years ago

Factor the trinomial: w^3-2w^2-8w

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  1. amistre64
    • 5 years ago
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    factor out the 'w;' and work the quad

  2. amistre64
    • 5 years ago
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    w,-4,2

  3. amistre64
    • 5 years ago
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    w(w-4)(w+2)

  4. anonymous
    • 5 years ago
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    do I have to have the w on the outside or can I put it in form (w-4)(w+2)

  5. amistre64
    • 5 years ago
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    the 'w' is a part of the factoring; it needs to be a part of the soultion or you dont get the same answer. That would be like saying; if I dont pay you for the first 3 hours you work, do you still get a full paycheck :)

  6. amistre64
    • 5 years ago
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    or numbers for example: 4(3)(2) = 24 ; can we omit the 4? ___(3)(2) = 6; cant do it ;)_

  7. anonymous
    • 5 years ago
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    ok well my work shows there are no letters on the outside of the parenthesis on any of the questions that are the same. So that is why I'm trying to figure out why urs does and theres dont

  8. amistre64
    • 5 years ago
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    are the problems you are looking at start with a 'w^3' ? 'w' being a dummy variable and any letter will work.

  9. amistre64
    • 5 years ago
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    the highest exponent in a problem is a good indicator of how many factors it will have

  10. amistre64
    • 5 years ago
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    x^2 can only have at most 2 factors x*x x^3 can only have at most 3 factors: x*x*x

  11. anonymous
    • 5 years ago
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    this is exactly what they give me Factor the trinomial w^3-2w^2-8w there showing me to pair of factors and sum of factors to get the answer

  12. amistre64
    • 5 years ago
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    first step; factor out all common elements: the 'w' w ( w^2 -2x -8 ) step 2: factor, if possible, the inside of the (...) w (w-4) (w+2) step 3: factor inside the (..) if possible. no other factors step 4: and.

  13. amistre64
    • 5 years ago
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    lol.... and means end :)

  14. anonymous
    • 5 years ago
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    what two numbers equal 2, and they have to be common factor of both 2 and 8

  15. amistre64
    • 5 years ago
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    -4(2) = -8 ... check -4+2 = -2 ... check

  16. amistre64
    • 5 years ago
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    (x+b)(x+c) = xx + xc +bx +bc x^2 +(b+c)x + b*c is how we form a quadratic

  17. amistre64
    • 5 years ago
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    to factor it, we need to find 'b' and 'c' that make the middle and last numbers

  18. amistre64
    • 5 years ago
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    x^2 + (-4+2)x + -4(2) x^2 -2x -8 ; you just gotta be able to see how its made... and that takes practice :)

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