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anonymous
 5 years ago
Use Newton's method to find an approximate solution for the equation
x^2+x=3
Start with x0=1 and iterate Newton's method twice to find x2.
anonymous
 5 years ago
Use Newton's method to find an approximate solution for the equation x^2+x=3 Start with x0=1 and iterate Newton's method twice to find x2.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f' = 2x + 1 f(0) = 3 x1 = x0  f(0) / f'(0) shoot  i'm not sure thats right  i'll have to check

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am also not sure, if you find anything about it pls post it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0newtons method is finding the equation of the tangent line; getting its root for a new x value to repeat the iteration right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Xn = f'(x)(xx0)+y0 = 0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(1,2) Xn = (2(1)+1)(x1)+2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Xn = 3x  1; Xn = 1/3 then right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do you label as Xn?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0new X value; Xn just seemed appropriate

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I coulda went with Larry, but.... i know a cucumber named Larry lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry still not clear, I am just working it out, but I dont see how you get y0=2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x^2 +x = 3 is that a typo?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x^2 +x = 3 ; when x=1 this is simply a false statement then 1+1 = 3???

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yep but the method will tend to the right answer

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0then remove the 0 to find some solutions

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0when x = 1; y = ? (1,1) then right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0use this point for your tangent equation that follows: yy0 = m(xx0) y = m(xx0)+y0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y = 3x4; the root is x = 4/3 then right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is why i did not see how that 2 appeared

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0:) right concept, wrong thought lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right and I should do this again to get the result, thanks for the help!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A mathematica solution with comments. Refer to the pdf attachment.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0andras:what/where are you studying?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0pure maths, just finished 1st year

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you on facebook? pardon me if posting this here is a breach of ettiquet

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:) I dont mind. Yes I am on facebook

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can add me if you wish but I dont use facebook that often. Andras Honyek

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0will do...I just sent you a request...neat...most people i know are glued to their fb accounts.
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