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anonymous

  • 5 years ago

f(t)=1.8(1.452)^t t=0 correspond to year2004. In what year will sales reach 20 billion?

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  1. anonymous
    • 5 years ago
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    you are trying to solve \[20=1.8(1.452)^t\] for t. divide by 1.8 \[\frac{20}{1.8}=(1.452)^t\] take the log of both sides \[\ln(\frac{20}{1.8})=\ln((1.452)^t)=t\ln(1.452)\]

  2. anonymous
    • 5 years ago
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    solve for t: \[t=\frac{\ln(\frac{20}{1.8})}{\ln(1.452)}\]

  3. anonymous
    • 5 years ago
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    thats what i got, but the answer would be 6.5 so the year 2010,

  4. anonymous
    • 5 years ago
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    i get 6.4 so 6.4 years after 2004 is 2010.4 of there abouts.

  5. anonymous
    • 5 years ago
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    but the question before asked what are sales in 2010 and my answer was 16.9.....not 20. im confused

  6. anonymous
    • 5 years ago
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    maybe be safe and say by 2011

  7. anonymous
    • 5 years ago
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    i guess the additional .5 counts! let me try it.

  8. anonymous
    • 5 years ago
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    thanks so much

  9. anonymous
    • 5 years ago
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    welcome!

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