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anonymous
 5 years ago
f(t)=1.8(1.452)^t t=0 correspond to year2004.
In what year will sales reach 20 billion?
anonymous
 5 years ago
f(t)=1.8(1.452)^t t=0 correspond to year2004. In what year will sales reach 20 billion?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you are trying to solve \[20=1.8(1.452)^t\] for t. divide by 1.8 \[\frac{20}{1.8}=(1.452)^t\] take the log of both sides \[\ln(\frac{20}{1.8})=\ln((1.452)^t)=t\ln(1.452)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0solve for t: \[t=\frac{\ln(\frac{20}{1.8})}{\ln(1.452)}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what i got, but the answer would be 6.5 so the year 2010,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i get 6.4 so 6.4 years after 2004 is 2010.4 of there abouts.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but the question before asked what are sales in 2010 and my answer was 16.9.....not 20. im confused

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0maybe be safe and say by 2011

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i guess the additional .5 counts! let me try it.
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