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anonymous

  • 5 years ago

4e^(X^2)=800 solve for x satellite where are you?

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  1. anonymous
    • 5 years ago
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    right here

  2. anonymous
    • 5 years ago
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    divide by 4

  3. anonymous
    • 5 years ago
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    \[e^{x^2}=200\]

  4. anonymous
    • 5 years ago
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    rewrite in equivalent logarithmic form

  5. anonymous
    • 5 years ago
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    \[x^2=\ln(200)\]

  6. anonymous
    • 5 years ago
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    solve for x: \[x=\pm\sqrt{\ln200}\]

  7. anonymous
    • 5 years ago
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    also note that \[ln(200)=ln(2\times 100)=ln(2)+ln(100)=ln(2)+ln(10^2)\] \[=ln(2)+2ln(10)\]

  8. anonymous
    • 5 years ago
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    not that this helps much

  9. anonymous
    • 5 years ago
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    k?

  10. anonymous
    • 5 years ago
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    for sure? i had x^2lne=ln200.....then x^2+1=ln 200.....is that wrong?

  11. anonymous
    • 5 years ago
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    ok but \[x^2\ln(e)=x^2\times 1 =x^2\]

  12. anonymous
    • 5 years ago
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    not \[x^2+1\]

  13. anonymous
    • 5 years ago
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    ohh......okay....i see why that was wrong. you are amazing ;)

  14. anonymous
    • 5 years ago
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    don't take that step in any case. remember that \[e^x=y\] says exactly the same thing as \[y=\ln(x)\]

  15. anonymous
    • 5 years ago
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    you are taking too many steps. write in "equivalent logarithmic form" and you will not have to mess with \[\ln(e)\]

  16. anonymous
    • 5 years ago
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    okay thank you

  17. anonymous
    • 5 years ago
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    welcome!

  18. anonymous
    • 5 years ago
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    i gotta run, do you have another quick one?

  19. anonymous
    • 5 years ago
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    convert log$3(22) into natural. is it ln22/ln3?

  20. anonymous
    • 5 years ago
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    yes change of base formula you have it.

  21. anonymous
    • 5 years ago
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    okay bye.wish i could put you in my pocket. hope to find you again

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