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anonymous
 5 years ago
Determine the coordinates of all points at which the tangent to the curve defined by y = x^2(e^x) is horizontal.
anonymous
 5 years ago
Determine the coordinates of all points at which the tangent to the curve defined by y = x^2(e^x) is horizontal.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tangents r horizontal slope=0 dy/dx=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok so this is the derivative that I got: y' = 1x^2 * e^x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Making it equal 0: 0 = 1x^2 * e^x < Now Im getting confused.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y'=2x(e^x)x^2(e^x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How did you get that? Oh wait You used product rule?
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