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anonymous

  • 5 years ago

find the quadratic equation that fits the following data points {(5,246),(-1,0)(4,160)}

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  1. amistre64
    • 5 years ago
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    i dont understand the notation

  2. amistre64
    • 5 years ago
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    is that just 3 points?

  3. amistre64
    • 5 years ago
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    i got something I made just for this lol

  4. anonymous
    • 5 years ago
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    {(5,246),(-1,0),(4,160)}

  5. amistre64
    • 5 years ago
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  6. amistre64
    • 5 years ago
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    we plug the points in and it spits a quad at us

  7. anonymous
    • 5 years ago
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    ok but what do i plug in

  8. amistre64
    • 5 years ago
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    9x^2 + 5x -4

  9. amistre64
    • 5 years ago
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    the data points

  10. amistre64
    • 5 years ago
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  11. anonymous
    • 5 years ago
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    where did u get 9x^2+5x-4

  12. amistre64
    • 5 years ago
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    well, I programed it to perform all that tedious calculations that I would do by hand from the data points and then tell me what I would have come to as a result

  13. anonymous
    • 5 years ago
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    i see u did the work for me

  14. amistre64
    • 5 years ago
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    its alot of solving for a system of equations in 3 variables

  15. anonymous
    • 5 years ago
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    thats what i was trying to do it sucks i always get stuck on whether to multiply (4) and (5)

  16. anonymous
    • 5 years ago
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    so to write it in standard y=a^2+bx+c would be y=9x^2+5x-4

  17. amistre64
    • 5 years ago
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    the equations are: 5^2a +5b +c =246 -1^2a -1b +c = 0 4^2a +4b +c =160

  18. amistre64
    • 5 years ago
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    yes

  19. anonymous
    • 5 years ago
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    great

  20. anonymous
    • 5 years ago
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    as usuall your a genious

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