I need help. I don't understand how to solve this equation. z^2-9z+18=0 Show Steps.

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I need help. I don't understand how to solve this equation. z^2-9z+18=0 Show Steps.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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first factor it (z-6)(z-3)=0 z = 6 or 3
because either z-6 = 0 or z-3 = 0
(-b(+-)sqrt(b^2-4ac))/2a. a=w^2 = 1 b=-7w = -7 c=-8 w= (7+-sqrt(49-4*(1*-8)))/2 = (7+-sqrt(81))/2 = (7+-9)/2 = 16/2 and -2/2 => w=8 V w=-1 I wrote this for a similar question. Just insert for a,b and c, and z instead of w, from the equation you provided. V is mathematical notation, meaning "and". So you'll have two answers for z, both equally correct.

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u don't need to do this as the function factorises
Thanks jimmyrep, I don't understand Msc.student ... Im only in Algebra 1
Yeah, but factorisation requires some intuition, meaning you'll have to have solved a lot of problems using it, to get the answers right consistently. I think a better place to start is the second degree equation.
I'm not familiar with how the American school works, so Algebra 1 doesn't mean much to me.
8th Grade
Oh, okay. Factorisation it is, then. You'll become familiar with the second degree equation soon enough.

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