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nice
 5 years ago
how to find the projection of a=(1,3) on b=(4,0,2) ??
nice
 5 years ago
how to find the projection of a=(1,3) on b=(4,0,2) ??

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0a onto b eh... vector right? its the a cos(angle between)

nice
 5 years ago
Best ResponseYou've already chosen the best response.0really ? I know diff. formula!!

nice
 5 years ago
Best ResponseYou've already chosen the best response.0angle is not mentioned at all in the question

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0t = \(cos^{1}(a.b/(ab))\)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0well, in order to know the length of the projection onto b you gotta know the angle between a and b

nice
 5 years ago
Best ResponseYou've already chosen the best response.0not the length ! it said just the vector that is proj.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0vectors are length and direction...cant have vector without length right?

nice
 5 years ago
Best ResponseYou've already chosen the best response.0sure! but I'm using the dot product ,, (a.b/b^2) x b

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0<1,3,0> <4,0,2>  4+0+0 =4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sqrt(10).sqt(20) = sqrt(200)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0cos_1(4/sqrt(200)) is what id try

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.073.57 degrees is the angle between them...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0but we already have the cos of that: 4/sqrt(200) lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.04sqrt(10)  = 4/sqrt(20) right? this is the length of a vector sqrt(10).sqrt(20) that is parallel to b

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0b/b = unit vector of b; then *that to get the vector projection

nice
 5 years ago
Best ResponseYou've already chosen the best response.0aha that the answer I've found but in diff. way

nice
 5 years ago
Best ResponseYou've already chosen the best response.0but the problem that it's multiple choice Qs. and I didn't find the answer !!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0<4,0,2> 4  *  :) sqrt(20) sqrt20

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i get: <16/20 , 0 ,8/20> if im right lol

nice
 5 years ago
Best ResponseYou've already chosen the best response.0the answers are : <1,1> , <2,1> , <2,1> , <1,2>

nice
 5 years ago
Best ResponseYou've already chosen the best response.0that's the answer I've got ! but it seems that its wrong !!!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0well, then we misunderstood what it was asking for then :)

nice
 5 years ago
Best ResponseYou've already chosen the best response.0the question which is up there is the exact same ques. !!!!!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, perhaps its the vector that I drew in green?

nice
 5 years ago
Best ResponseYou've already chosen the best response.0thanks allot for trying ..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0a.b  * b b^2 4/20 = 1/5<4,0,2> = <4/5,0,2/5> cant really see it being nuthin else

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0youre welcome :) good luck

nice
 5 years ago
Best ResponseYou've already chosen the best response.0yes! that's my opinion two !
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