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anonymous

  • 5 years ago

Here is a good one. :) A manufacturer is designing special packaging for a product in the shape of a truncated pyramid. A truncated pyramid is a pyramid with the top cut off. The model he is building is included. The bases are not regular figures. The lateral sides are trapezoids. The height of each trapezoid face is 12 cm. Determine the amount of material needed to build the model (assume no overlap on the sides).

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  1. anonymous
    • 5 years ago
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  2. mathteacher1729
    • 5 years ago
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    Find the area of the big pyramid, and subtract from that the area of the little pyramid. Be careful to ADD BACK the base of the small pyramid since it will be the top of the package. Hope this helps.

  3. anonymous
    • 5 years ago
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    thank you I will give it a shot! :)

  4. dumbcow
    • 5 years ago
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    normally i would agree but in this case you dont know the height of the triangular faces, only the height of the trapezoids use area of trapezoid formula (1/2*h(b1+b2)) to find area of all 3 trapezoid faces then add the 2 right triangle areas (top and bottom) i get 246

  5. anonymous
    • 5 years ago
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    yes I have the formula for the trapezoid

  6. anonymous
    • 5 years ago
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    Ill check mine

  7. amistre64
    • 5 years ago
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    6(3+6) + 6(4+8) + 6(5+10) +2(3) + 4(6) = Sa from my point of view

  8. amistre64
    • 5 years ago
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    54 + 72 + 90 + 6 +24 120 + 126 = 246

  9. anonymous
    • 5 years ago
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    i just got that... yes it matches both :)

  10. anonymous
    • 5 years ago
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    and that is how much material is needed ..... 246 cm^2

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