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anonymous

  • 5 years ago

\[f(x)=4(x-2)^{2}-1\] vertex?

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  1. mathteacher1729
    • 5 years ago
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    Have you tried graphing? :)

  2. immanuelv
    • 5 years ago
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    (2, -1)

  3. anonymous
    • 5 years ago
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    (2,-1)

  4. anonymous
    • 5 years ago
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    nope not yet

  5. anonymous
    • 5 years ago
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    it is displayed for you.

  6. myininaya
    • 5 years ago
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    you don't have to graph this to find the vertex it is (2,-1)

  7. anonymous
    • 5 years ago
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    \[f(x)=a(x-h)^2+k\] has vertex (h,k)

  8. myininaya
    • 5 years ago
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    i was just fixing to say that :(

  9. anonymous
    • 5 years ago
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    what would the x-intercept of parabola for this would be??

  10. myininaya
    • 5 years ago
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    set y=0 and solve for x

  11. anonymous
    • 5 years ago
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    ????

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