Solve using the addition and multiplication principles
3 1 2 1
_ _ _ -
4 (3x - 2) - 3 < 3

- anonymous

Solve using the addition and multiplication principles
3 1 2 1
_ _ _ -
4 (3x - 2) - 3 < 3

- chestercat

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- anonymous

12x - 8 -3 < 3
12x < 3 + 3 + 8
12x < 14
x < 14/12
x < 7/6

- anonymous

wow

- anonymous

do u mind clarfyin

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## More answers

- anonymous

do u follow that ok?

- anonymous

no

- anonymous

You need to use the distributive property and distribute the 4 to the 3x making it 12x and the 4 to the -2 making it -8

- anonymous

well to be honest i dont know what you mean by the multiplication and addition principles. i know that i've got the right answer but i dont want to confuse you

- anonymous

o ok thats what the instruction says... i see how u got the bottom what about the top?

- anonymous

what do you mean?

- anonymous

they are fractions

- anonymous

yes i used the distribution principle in my first line

- anonymous

3/4
1/2 and so on

- anonymous

You need to get x by itself.

- anonymous

Then you reduce it.

- anonymous

sight up so with how jim worked it out thats final? and jim im not goin against just ask

- dumbcow

write fractions more clearly...1/2
what you wrote is confusing

- anonymous

It looks right. You can put this into a TI-89 or HP48/50 and have it do it for you.

- anonymous

it was even more confusing but its identical to the textbook

- anonymous

its wrote just as that

- anonymous

i have a Ti-89

- anonymous

TI-89 does all Algebra for you.

- anonymous

i had to write it that way cause the parethesis

- anonymous

You have to to show that you need to distribute.

- dumbcow

\[\frac{3}{4}(3x-\frac{1}{2}) - \frac{2}{3} <\frac{1}{3}\]

- anonymous

yes thats correct cow

- anonymous

TI-89 can do that.

- anonymous

OH!, then I might have been wrong.

- anonymous

how? barley know how to work that calc

- anonymous

I only did 4 (3x - 2) - 3 < 3

- anonymous

yes i see

- anonymous

Find "solve("

- anonymous

Put in the problem like Cow did.

- anonymous

then do ",x)

- anonymous

"

- anonymous

sightup i have no idea of what ur tryn to say

- dumbcow

\[x <\frac{11}{18}\]

- anonymous

On your TI-89...

- anonymous

Another awesome utility to learn is wolframalpha.

- anonymous

http://www.wolframalpha.com/

- anonymous

cow what steps?

- anonymous

ok sightup ima check it out

- anonymous

Same steps, distribute, combine like terms and get x by itself. ALWAYS.

- anonymous

so sightup just as u did do u think u can show work to get this sum that he got

- anonymous

Let me work it out quick.

- anonymous

k

- anonymous

I get the same answer.

- anonymous

You need to know how tho?

- anonymous

i went to the sight u gave

- anonymous

same answer yes but i need to see the work

- anonymous

ok its like this.

- anonymous

first thing like i said is distribute.

- anonymous

9x/4 - 3/8 -2/3 < 1/3

- anonymous

we are going to move over the - 3/8 -2/3 so it now read like so: 9x/4 < 1/3 + 3/8 + 2/3

- anonymous

combine like terms.

- anonymous

9x/4<11/8 is what we get

- anonymous

just times it now and you get your answer.

- anonymous

great thanx for showing me that!

- anonymous

learn to use your TI-89 and you will never have to do algebra again.

- anonymous

i need lessons um where can i get info on that?

- anonymous

youtube.com... just type how to ..... ti-89

- anonymous

o ok kool

- anonymous

how to solve for 0 ti-89 for example

- anonymous

or x

- anonymous

i got to pee ttyl.

- anonymous

k

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