anonymous
  • anonymous
Solve using the addition and multiplication principles 3 1 2 1 _ _ _ - 4 (3x - 2) - 3 < 3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
12x - 8 -3 < 3 12x < 3 + 3 + 8 12x < 14 x < 14/12 x < 7/6
anonymous
  • anonymous
wow
anonymous
  • anonymous
do u mind clarfyin

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anonymous
  • anonymous
do u follow that ok?
anonymous
  • anonymous
no
anonymous
  • anonymous
You need to use the distributive property and distribute the 4 to the 3x making it 12x and the 4 to the -2 making it -8
anonymous
  • anonymous
well to be honest i dont know what you mean by the multiplication and addition principles. i know that i've got the right answer but i dont want to confuse you
anonymous
  • anonymous
o ok thats what the instruction says... i see how u got the bottom what about the top?
anonymous
  • anonymous
what do you mean?
anonymous
  • anonymous
they are fractions
anonymous
  • anonymous
yes i used the distribution principle in my first line
anonymous
  • anonymous
3/4 1/2 and so on
anonymous
  • anonymous
You need to get x by itself.
anonymous
  • anonymous
Then you reduce it.
anonymous
  • anonymous
sight up so with how jim worked it out thats final? and jim im not goin against just ask
dumbcow
  • dumbcow
write fractions more clearly...1/2 what you wrote is confusing
anonymous
  • anonymous
It looks right. You can put this into a TI-89 or HP48/50 and have it do it for you.
anonymous
  • anonymous
it was even more confusing but its identical to the textbook
anonymous
  • anonymous
its wrote just as that
anonymous
  • anonymous
i have a Ti-89
anonymous
  • anonymous
TI-89 does all Algebra for you.
anonymous
  • anonymous
i had to write it that way cause the parethesis
anonymous
  • anonymous
You have to to show that you need to distribute.
dumbcow
  • dumbcow
\[\frac{3}{4}(3x-\frac{1}{2}) - \frac{2}{3} <\frac{1}{3}\]
anonymous
  • anonymous
yes thats correct cow
anonymous
  • anonymous
TI-89 can do that.
anonymous
  • anonymous
OH!, then I might have been wrong.
anonymous
  • anonymous
how? barley know how to work that calc
anonymous
  • anonymous
I only did 4 (3x - 2) - 3 < 3
anonymous
  • anonymous
yes i see
anonymous
  • anonymous
Find "solve("
anonymous
  • anonymous
Put in the problem like Cow did.
anonymous
  • anonymous
then do ",x)
anonymous
  • anonymous
"
anonymous
  • anonymous
sightup i have no idea of what ur tryn to say
dumbcow
  • dumbcow
\[x <\frac{11}{18}\]
anonymous
  • anonymous
On your TI-89...
anonymous
  • anonymous
Another awesome utility to learn is wolframalpha.
anonymous
  • anonymous
http://www.wolframalpha.com/
anonymous
  • anonymous
cow what steps?
anonymous
  • anonymous
ok sightup ima check it out
anonymous
  • anonymous
Same steps, distribute, combine like terms and get x by itself. ALWAYS.
anonymous
  • anonymous
so sightup just as u did do u think u can show work to get this sum that he got
anonymous
  • anonymous
Let me work it out quick.
anonymous
  • anonymous
k
anonymous
  • anonymous
I get the same answer.
anonymous
  • anonymous
You need to know how tho?
anonymous
  • anonymous
i went to the sight u gave
anonymous
  • anonymous
same answer yes but i need to see the work
anonymous
  • anonymous
ok its like this.
anonymous
  • anonymous
first thing like i said is distribute.
anonymous
  • anonymous
9x/4 - 3/8 -2/3 < 1/3
anonymous
  • anonymous
we are going to move over the - 3/8 -2/3 so it now read like so: 9x/4 < 1/3 + 3/8 + 2/3
anonymous
  • anonymous
combine like terms.
anonymous
  • anonymous
9x/4<11/8 is what we get
anonymous
  • anonymous
just times it now and you get your answer.
anonymous
  • anonymous
great thanx for showing me that!
anonymous
  • anonymous
learn to use your TI-89 and you will never have to do algebra again.
anonymous
  • anonymous
i need lessons um where can i get info on that?
anonymous
  • anonymous
youtube.com... just type how to ..... ti-89
anonymous
  • anonymous
o ok kool
anonymous
  • anonymous
how to solve for 0 ti-89 for example
anonymous
  • anonymous
or x
anonymous
  • anonymous
i got to pee ttyl.
anonymous
  • anonymous
k

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