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anonymous

  • 5 years ago

\[f(x)=4(x+1)^{2}-2\] x-intercept of parabola?

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  1. myininaya
    • 5 years ago
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    aimstre just answered this lol

  2. anonymous
    • 5 years ago
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    \[(4)(x+1)^2-2=0\] \[4(x+1)^2=2\] \[(x+1)^2=\frac{1}{4}\] \[x+1=\pm\sqrt{\frac{1}{4}}=\pm\frac{1}{2}\]

  3. anonymous
    • 5 years ago
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    \[x=-1+\frac{1}{2}=-\frac{1}{2}\]

  4. myininaya
    • 5 years ago
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    oh no 2/4=1/2 not 1/4

  5. anonymous
    • 5 years ago
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    or \[x=-1-\frac{1}{2}= -\frac{3}{2}\]

  6. anonymous
    • 5 years ago
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    ?

  7. myininaya
    • 5 years ago
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    (x+1)^2=1/2

  8. anonymous
    • 5 years ago
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    ooooooooooooooooops

  9. anonymous
    • 5 years ago
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    sorry myininaya is right and i am wrong

  10. myininaya
    • 5 years ago
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    :) i like to hear that more

  11. anonymous
    • 5 years ago
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    \[(x+1)^2=\frac{1}{2}\]

  12. anonymous
    • 5 years ago
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    this is not right...

  13. anonymous
    • 5 years ago
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    \[x+1=\pm\sqrt{\frac{1}{2}}\]

  14. anonymous
    • 5 years ago
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    \[x=-1\pm\frac{1}{\sqrt{2}}\]

  15. myininaya
    • 5 years ago
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    gj satellitle i knew you could do it

  16. amistre64
    • 5 years ago
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    yay!! lol

  17. anonymous
    • 5 years ago
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    hope so! i just wrote that 2/4 = 1/4 instead of1/2!

  18. myininaya
    • 5 years ago
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    lol

  19. anonymous
    • 5 years ago
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    must be time for some holy wine!

  20. myininaya
    • 5 years ago
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    maybe it does and we just have been doing math wrong all these years

  21. myininaya
    • 5 years ago
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    satellite the bat signal is out i mean the satellite signal is out

  22. anonymous
    • 5 years ago
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    could be. btw to tinka, there are many ways to write \[1+\frac{1}{\sqrt{2}}\]

  23. anonymous
    • 5 years ago
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    or even \[-1+\frac{1}{\sqrt{2}}\]

  24. myininaya
    • 5 years ago
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    someone is requesting you

  25. anonymous
    • 5 years ago
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    me?

  26. myininaya
    • 5 years ago
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    top post

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