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anonymous

  • 5 years ago

6*2^2x - 13*6^x + 6*3^2x = 0 what is the value of X ?

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  1. Owlfred
    • 5 years ago
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    Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

  2. anonymous
    • 5 years ago
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    you sure you typed that right?

  3. myininaya
    • 5 years ago
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    lets see if we can factor 6u^2-13uv+6v^2=0

  4. anonymous
    • 5 years ago
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    I get x=1

  5. anonymous
    • 5 years ago
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    how

  6. myininaya
    • 5 years ago
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    see if this helpful to you k?

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  7. anonymous
    • 5 years ago
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    so what's your answer ?

  8. myininaya
    • 5 years ago
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    3u-2v=0 implies we have 3u=2v 2u-3v=0 implies we have 2u=3v remember u=2^x and v=3^x so we have \[3*2^x=2*3^x \] and \[2*2^x=3*3^x\]

  9. myininaya
    • 5 years ago
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    get your x on one side 3/2=3^x/2^x 3/2=(3/2)^x so x=1 for the first equation

  10. myininaya
    • 5 years ago
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    2/3=3^x/2^x 2/3=(3/2)^x x=-1 for the second

  11. anonymous
    • 5 years ago
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    thanks

  12. anonymous
    • 5 years ago
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    but

  13. myininaya
    • 5 years ago
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    i will leave the checking part to you

  14. anonymous
    • 5 years ago
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    how you 13uv is = -4uv-9uv

  15. myininaya
    • 5 years ago
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    i was trying to factor to factor you look for factors of a*c that add up to be b 6(6)=36 (-4)(-9)=36 -4-9=-13

  16. anonymous
    • 5 years ago
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    ok

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