anonymous
  • anonymous
6*2^2x - 13*6^x + 6*3^2x = 0 what is the value of X ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Owlfred
  • Owlfred
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anonymous
  • anonymous
you sure you typed that right?
myininaya
  • myininaya
lets see if we can factor 6u^2-13uv+6v^2=0

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anonymous
  • anonymous
I get x=1
anonymous
  • anonymous
how
myininaya
  • myininaya
see if this helpful to you k?
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anonymous
  • anonymous
so what's your answer ?
myininaya
  • myininaya
3u-2v=0 implies we have 3u=2v 2u-3v=0 implies we have 2u=3v remember u=2^x and v=3^x so we have \[3*2^x=2*3^x \] and \[2*2^x=3*3^x\]
myininaya
  • myininaya
get your x on one side 3/2=3^x/2^x 3/2=(3/2)^x so x=1 for the first equation
myininaya
  • myininaya
2/3=3^x/2^x 2/3=(3/2)^x x=-1 for the second
anonymous
  • anonymous
thanks
anonymous
  • anonymous
but
myininaya
  • myininaya
i will leave the checking part to you
anonymous
  • anonymous
how you 13uv is = -4uv-9uv
myininaya
  • myininaya
i was trying to factor to factor you look for factors of a*c that add up to be b 6(6)=36 (-4)(-9)=36 -4-9=-13
anonymous
  • anonymous
ok

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