anonymous
  • anonymous
solve over the interval [0,2 pi): tan 3x=the negative square root of 3
Mathematics
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[\tan 3x=-\sqrt{3}\]
amistre64
  • amistre64
thats in Q2 or Q4
amistre64
  • amistre64
tan(60)

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amistre64
  • amistre64
so x = 20, 40 are 2 of em
amistre64
  • amistre64
20 aint right lol
amistre64
  • amistre64
2pi/9
amistre64
  • amistre64
5pi/9
amistre64
  • amistre64
120pi/(180)3 and 300pi/(180)3 maybe lol
anonymous
  • anonymous
\[\text{Tan}[3x]= -\sqrt{3}\]\[\text{ArcTan}[\text{Tan}[3x]]=\text{ArcTan}\left[-\sqrt{3}\right] \]\[3 x=-\frac{\pi }{3}\]\[x=-\frac{\pi }{9}\]Problem calls for positive angles between 0 and 2 pi\[x=\frac{8 \pi }{9} \text{and } x=\frac{17 \pi }{9} \]

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