anonymous
  • anonymous
solve :- log(cubic root of 3X-1) + log(cubic root of 3x+1) =log 20-1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\log \sqrt[3]{3X-1} + \log \sqrt[3]{3X+1} =\log 20-1\]
amistre64
  • amistre64
emun can do it :)
anonymous
  • anonymous
yeah

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anonymous
  • anonymous
give me a minute to finish it
anonymous
  • anonymous
fast plz
anonymous
  • anonymous
1 Attachment
amistre64
  • amistre64
i mighta missed it lo
anonymous
  • anonymous
not sure. That is what i got. Correct me if im wrong.
anonymous
  • anonymous
wrong
amistre64
  • amistre64
1.27614 maybe lol
anonymous
  • anonymous
no
anonymous
  • anonymous
1 , -1
anonymous
  • anonymous
you have to isolate x now
anonymous
  • anonymous
why U made the power 1/3 to 3
anonymous
  • anonymous
answer me
anonymous
  • anonymous
ahhh ok. Yeah definitively im wrong
anonymous
  • anonymous
gonna try to solve it.
anonymous
  • anonymous
U R welcome
anonymous
  • anonymous
Sorry i modified that, but i didnt get 1, -1
anonymous
  • anonymous
so what did U get
anonymous
  • anonymous
hah
anonymous
  • anonymous
answer me
anonymous
  • anonymous
something that you would make fun of. I have to have diner now. I'll answer you later. just be pacient
anonymous
  • anonymous
Here you have
anonymous
  • anonymous
wrong
anonymous
  • anonymous
look
anonymous
  • anonymous
Can you realize in what part I mess up?
anonymous
  • anonymous
log 20/10 = log 2
anonymous
  • anonymous
I didt do that anywhere
anonymous
  • anonymous
I dont need that process
anonymous
  • anonymous
sorry at the end
anonymous
  • anonymous
\[(3X-1)(3X+1) = 8\]
anonymous
  • anonymous
it must be
anonymous
  • anonymous
You are right, but the mistake is at the begining. Gonna try to solve it again
anonymous
  • anonymous
\[9 x ^{2 } + 1 = 8\]
anonymous
  • anonymous
\[9 X ^{2} = 9\]
anonymous
  • anonymous
X = 1 , -1 s.s = {1}
anonymous
  • anonymous
-1 ref..
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
yeah you were right :)
anonymous
  • anonymous
Hope I was helpful here
anonymous
  • anonymous
U r always
anonymous
  • anonymous
but
anonymous
  • anonymous
but ... too slow
anonymous
  • anonymous
noooooooooooooooo
anonymous
  • anonymous
\[10^{\log20} *10^{-1}\]
anonymous
  • anonymous
or \[10^{\log20} - 10^{-1}\]
anonymous
  • anonymous
the first one, because \[a ^{m}a ^{n}=a ^{m+n}\]
anonymous
  • anonymous
clear?
anonymous
  • anonymous
ok
anonymous
  • anonymous
can you give me a medal please :) I think I deserve it
anonymous
  • anonymous
but how
myininaya
  • myininaya
1 Attachment
anonymous
  • anonymous
^ *cough*
anonymous
  • anonymous
forget something myininaya?
myininaya
  • myininaya
lol the 1 (x-1)(x+1)=0
anonymous
  • anonymous
no, you are saying the solution is x=+-1 , are you sure :P
myininaya
  • myininaya
well its not -1 because we can't have log of negative number
myininaya
  • myininaya
so its just x=1 i was hoping he would know to do that but you are right i should had said that
anonymous
  • anonymous
but I know
anonymous
  • anonymous
this all in my studies

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