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anonymous

  • 5 years ago

need help with simplifying by rationalizing the denominator.

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  1. Owlfred
    • 5 years ago
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    Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

  2. anonymous
    • 5 years ago
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    when you have: \[\frac{a}{b-\sqrt{c}}\] multiply the top and bottom by the conjugate: b+sqrt(c) \[\frac{a(b+\sqrt{c})}{(b-\sqrt{c})(b+\sqrt{c})}=\frac{ab+a \sqrt{c}}{b^{2}-c}\]

  3. anonymous
    • 5 years ago
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    now the denominator is rational

  4. anonymous
    • 5 years ago
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    Rationalizing the denominator requires that you multiply above and below by the contents of the denominator. So in this case, you need to multiply above and below by \[b-\sqrt{c}\] This will give you a new result of \[a(b-\sqrt{c})/b-\sqrt{c})^2\]

  5. anonymous
    • 5 years ago
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    (b-sqrt(c))^2=b^2-2bsqrt(c)+c, this is not rational. you need to multiply by the conjugate to get rid of the radical

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