anonymous
  • anonymous
\[x ^{-2}-4x ^{-1}=0\] Help me
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
This can be rewritten as \[1/x^2-1/4x=0\] If you plug this into a TI-89 using the solve function, you get: \[x=1/4\] Hope this helps.
anonymous
  • anonymous
factor the left side into \[\frac{1}{x}(\frac{1}{x}-4)=0\]and set the factors equal to zero. \[\frac{1}{x}=0\] is not true for any real x, so this gives no solutions. \[\frac{1}{x}-4=0\] gives \[\frac{1}{x}=4\]and so, multiplying both sides by x and dividing by 4, \[x=\frac{1}{4}\]
anonymous
  • anonymous
got this one :)

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anonymous
  • anonymous
\[\frac{1}{x ^{2}}-\frac{4}{x}=10\]\[Denominator is: x ^{2}\]\[\frac{1*x}{x ^{2}}-\frac{4*x}{x*x}=10*x^2\]get rid with denominator\[1-4x=10x ^{2}\]\[10x ^{2}-4x+1=0\]\[\frac{-(-4)\pm \sqrt{-4^{2}-(-4\times10\times1)}}{2\times10}\]\[\frac{4\pm \sqrt{16+40}}{20}\]\[\frac{4\pm 2\sqrt{14}}{20}\]\[\frac{2\pm \sqrt{14}}{10}\]

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