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anonymous
 5 years ago
\[x ^{2}4x ^{1}=0\]
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anonymous
 5 years ago
\[x ^{2}4x ^{1}=0\] Help me

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This can be rewritten as \[1/x^21/4x=0\] If you plug this into a TI89 using the solve function, you get: \[x=1/4\] Hope this helps.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0factor the left side into \[\frac{1}{x}(\frac{1}{x}4)=0\]and set the factors equal to zero. \[\frac{1}{x}=0\] is not true for any real x, so this gives no solutions. \[\frac{1}{x}4=0\] gives \[\frac{1}{x}=4\]and so, multiplying both sides by x and dividing by 4, \[x=\frac{1}{4}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{1}{x ^{2}}\frac{4}{x}=10\]\[Denominator is: x ^{2}\]\[\frac{1*x}{x ^{2}}\frac{4*x}{x*x}=10*x^2\]get rid with denominator\[14x=10x ^{2}\]\[10x ^{2}4x+1=0\]\[\frac{(4)\pm \sqrt{4^{2}(4\times10\times1)}}{2\times10}\]\[\frac{4\pm \sqrt{16+40}}{20}\]\[\frac{4\pm 2\sqrt{14}}{20}\]\[\frac{2\pm \sqrt{14}}{10}\]
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