A bag contains 7 nickels, 4 dimes, & 8 quarters. If you draw 3 coins at random from the bag, without replacement, what is the probability that you will get a nickel, a quarter, and a nickel, in that order?

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A bag contains 7 nickels, 4 dimes, & 8 quarters. If you draw 3 coins at random from the bag, without replacement, what is the probability that you will get a nickel, a quarter, and a nickel, in that order?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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there are 19 coins total so first to get a nickel 7/19 than there are only 18 coins left so to get a quarter is 8/18 than there is only 17 left but only 6 nickels so that is 6/17 As all the events are independent the total probability is there product so 7*8*6/(19*18*17)
my options are : 22/57, 392/6859, 7/18, 56/969, or 196/2907
7*8*6/19*18*17=7*8/(19*3*17)=56/969

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